Harry took a loan from the bank. D(t) models Harry's remaining debt (in dollars) as a function of time, t (in months)

Mathematics

2 answers:

pogonyaev3 years ago

6 0

Answer:

200

Step-by-step explanation:

i took the quiz and i got it right hope this kinda helps :)))

Zarrin [17]3 years ago

4 0

Answer-

The size of Harry's loan is $9000.

Solution-

Harry took a loan from the bank.

D(t) is the function that models Harry's remaining debt, in dollars, as a function of time t, in months

The function is given by,

$D(t) = -200t + 9000$

From this function this can be obtained that, 200 is getting deducted from the function, i.e Harry is paying $200 each month towards his loan.

We can get the total amount of Harry's lone by putting t=0, because at the beginning Harry has not paid anything. So, the value of D(t) will give the net amount of loan.

$\Rightarrow D(t) = -200(0) + 9000$

$\Rightarrow D(t) =9000$

Therefore, the size of Harry's loan is $9000.

You might be interested in

Graph the function and analyze it for domain, range, continuity, increasing or decreaseing behavior, symmetry, boundedness, extr

Sunny_sXe [5.5K]

Answer:

$f(x) = 3 \cdot 0.2^x$

Step-by-step explanation:

$f(x) = 3 \cdot 0.2^x$

Domain of f: "What values of x can we plug into this equation?" This makes sense for all real numbers so the domain is $\mathbb{R}$

Range of f: "What values of f(x) can we get out of the function?" From the graph we see we can get any real number greater than 0 out of the function by choosing a suitable x-value in the domain. The range is therefore $(0, \infty)$ .

Continuity: Since the graph is one, unbroken curve (i.e. a curve that can be drawn in one movement without taking your pen off the paper). We see that "roughly speaking" the function is continuous.

Increasing or decreasing behaviour: For all x in the domain, as x increases, f(x) decreases. This means the function exhibits decreasing behaviour.

Symmetry: It is clear to see the graph of f(x) has no symmetry.

Boundedness: Looking at the graph we see it is unbounded above as when we choose negative values, the graph of f(x) explodes upwards exponentially. Choose a value of x, plug it in, next choose (x-1), plug this in and we observe $f(x-1) > f(x)$ for all x in the domain.

The function is however bounded below by 0: no value of x in the domain exists which satisfies $f(x) < 0$ .

Extrema: As far as I can tell, there are no turning points on the curve. (Is this what you mean by extrema?)

Asymptotes: Contrary to the curve's appearance, there are no vertical asymtotes for this curve. The negative-x portion of the curve is just growing so quickly it appears to look like an asymptote. There is a value of f(x) for all x<0. There is however a horizontal asymtote: $y=0$ .