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kondor19780726 [428]
3 years ago
7

18. Find the equation of the circle containing the points (-1.-1) and (3, 1) and with the centre on the line x-y + 10 = 0​

Mathematics
1 answer:
Vlad [161]3 years ago
3 0

Answer:

x^{2} +2x+y^{2}+2y= 18

Step-by-step explanation:

equation of circle is:

x^{2}+y^{2}=r^{2}

using distance formula and substituting value,

(3-(-1))^{2} +(1-(-1))^{2}=r^{2}

solving,

r=2\sqrt{5}

for equation of circle,

(x-(-1))^{2} +(y-(-1))^{2} =20

on solving,

x^{2} +2x+1+y^{2}+2y+1=20

on solving,

x^{2} +2x+y^{2}+2y= 18

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The lengths of the line segments are summarized in the following list:

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<h3>How to calculate the length of a line segment based on point set on a number line</h3>

Herein we have a number line with five points whose locations are known.  The length of each line segment is equal to the arithmetical difference of the coordinates of the rightmost point and the leftmost point:

DF = - 1 - (- 4)

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To learn more on lengths: brainly.com/question/8552546

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