Question

18. Find the equation of the circle containing the points (-1.-1) and (3, 1) and with the centre on the line x-y + 10 = 0​

Answer 1

Answer:

x^{2} +2x+y^{2}+2y= 18

Step-by-step explanation:

equation of circle is:

$x^{2}+y^{2}=r^{2}$

using distance formula and substituting value,

$(3-(-1))^{2} +(1-(-1))^{2}=r^{2}$

solving,

r=$2\sqrt{5}$

for equation of circle,

$(x-(-1))^{2} +(y-(-1))^{2} =20$

on solving,

$x^{2} +2x+1+y^{2}+2y+1=20$

on solving,

$x^{2} +2x+y^{2}+2y= 18$