Https://www.khanacademy.org/math/in-sixth-grade-math/ratio-and-proportion/unitary-method/v/finding-unit-rates
9514 1404 393
Answer:
- square: 12 ft sides
- octagon: 6 ft sides
Step-by-step explanation:
This problem can be worked in your head.
If the perimeters of the square and regular octagon are the same, the side length of the 4-sided square must be the same as the length of 2 sides of the 8-sided octagon. Since the side of the square is 6 ft more than the side of the octagon, each side of the octagon must be 6 ft, and each side of the square must be 12 ft.
__
We can let s represent the side length of the octagon. Then we have ...
8s = perimeter of octagon
4(s +6) = perimeter of square
These are equal, so ...
4(s +6) = 8s
s +6 = 2s . . . . . . divide by 4
6 = s . . . . . . . . . . subtract s
The octagon has 6-ft sides; the square has 12-ft sides.
Question:
Yan is climbing down a ladder. Each time he descends 4 rungs on the ladder, he stopped to see how much farther he has to go. If Yan made eight stops with no extra steps, which expression best shows another way to write the product of the number of ladder rungs that Yan and climbed?
4+4+4+4
8+8+8+8
(-1)(4+4+4+4)
(-8) + (-8) + (-8) + (-8)
Answer:
Step-by-step explanation:
Given
<em></em>
<em> --- It is negative because he is climbing down</em>

Required
An expression for the number of rungs climbed
To do this, we simply multiply the number of rungs by the steps taken.


This can be rewritten as:

The product, when written as sum is:
The density of aluminum is known to be 2.70 g/cm3