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shusha [124]
3 years ago
14

The length of a rectangle is 4 in longer than its width.

Mathematics
1 answer:
sertanlavr [38]3 years ago
3 0

Answer:

60 sq in

Step-by-step explanation:

Perimeter = 2l + 2w

If l = w+4

Perimeter = 2(w+4) + 2w

Perimeter = 4w+8

32 = 4w + 8

24 = 4w

6 = w

If w = 6, l = 6+4 = 10

Area = l * w

Area = 10 * 6

Area = 60

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nika2105 [10]

Answer:

sin = o/h = 5/13

cos = a/h = 12/13

tan = o/a = 5/12

o - opposite

a- adjacent

h - hypotenuse

6 0
2 years ago
Evaluate the expression when x= -7.4 and y= -6.3<br>-7y+2x​
GenaCL600 [577]

Answer:  -29.3

Step-by-step explanation:  -7y + 2x

-7(-6.3) + 2(-7.4) = -29.3

5 0
3 years ago
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There are 6 blue marbles, 3 red marbles, and 5 yellow marbles in a bag. What is the probability of selecting a blue or red marbl
STALIN [3.7K]
8.5 and the thing is 5/2
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3 years ago
In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60
Olegator [25]

Answer:

7.38-1.96\frac{2.51}{\sqrt{601}}=7.18    

7.38+1.96\frac{2.51}{\sqrt{601}}=7.58    

For this case the confidence interval is given by :

7.18 \leq \mu \leq 7.58

Step-by-step explanation:

Data provided

\bar X=7.38 represent the sample mean for the fuel efficiencies

\mu population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size  

Confidence interval

The formula for the confidence interval of the true mean is given by:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom for this case is given by:

df=n-1=601-1=600

The Confidence level for this case is 0.95 or 95%, and the significance level \alpha=0.05 and \alpha/2 =0.025 and the critical value is given by t_{\alpha/2}=1.96

Replcing into the formula for the confidence interval is given by:

7.38-1.96\frac{2.51}{\sqrt{601}}=7.18    

7.38+1.96\frac{2.51}{\sqrt{601}}=7.58    

For this case the confidence interval is given by :

7.18 \leq \mu \leq 7.58

8 0
3 years ago
Solve the inequality 4t^2 ≤ 9t-2 please show steps and interval notation. thank you!​
FromTheMoon [43]

Answer: t\in [\dfrac{1}{4},2]

Step-by-step explanation:

Given

Inequality is 4t^2\leq9t-2

Taking variables one side

\Rightarrow 4t^2-9t+2\leq0\\\Rightarrow 4t^2-8t-t+2\leq0\\\Rightarrow 4t(t-2)-1(t-2)\leq0\\\Rightarrow (4t-1)(t-2)\leq0

Using wavy curve method

t\in [\dfrac{1}{4},2]

3 0
2 years ago
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