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charle [14.2K]
3 years ago
15

Unit rate of 51 gallons in 14 minutes

Mathematics
2 answers:
ruslelena [56]3 years ago
6 0
3.64 gallons per minute
Goshia [24]3 years ago
6 0

51g / 14 min = 3.64...

Unite Rate = 3.64

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4 0
3 years ago
A triangle has vertices at (2, 3), (-4, 5), and (-3, 4). What are the coordinates of the vertices
elena-s [515]

(2,3) \longrightarrow (2+1, 3-3)=\boxed{(3,0)}\\(-4,5) \longrightarrow (-4+1, 5-3)=\boxed{(-3, 2)}\\(-3,4) \longrightarrow (-3+1, 4-3)=\boxed{(-2, 1)}

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A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and
IRINA_888 [86]

Answer:

<em>The approximate percentage of cars that remain in service between 73 and 84 months</em>

<em>P( 73 < x < 84 ) = 0.02145 = 2.1 %</em>

<u>Step-by-step explanation</u>:

<u><em>Explanation</em></u>:-

Given mean of the Population 'μ ' = 51 months

Standard deviation of the Population 'σ' = 11 months

Let 'X' be the random variable of Normal distribution

<em>Let    'X'  = 73</em>

<em></em>Z = \frac{x-mean}{S.D} = \frac{73-51}{11} = 2<em></em>

<em>Let  'X' = 84</em>

<em></em>Z = \frac{84-51}{11} = 3<em></em>

<em>The approximate percentage of cars that remain in service between 73 and 84 months</em>

<em>P( 73 < x < 84 )      = P( 2 < Z < 3)</em>

<em>                               = P( Z<3) - P( Z <2)</em>

<em>                              =  0.5 + A(3) - ( 0.5 + A(2))</em>

<em>                             = A(3) - A( 2)</em>

<em>                             = 0.49865 - 0.4772     ( From Normal table)</em>

<em>                             = 0.02145</em>

<em>  P( 73 < x < 84 ) = 0.02145</em>

<em>The approximate percentage of cars that remain in service between 73 and 84 months</em>

<em>P( 73 < x < 84 ) = 0.02145 = 2.1 %</em>

7 0
3 years ago
Solve for x and y simultaneously <br><br>Pls help me​
LenKa [72]

Step-by-step explanation:

Are the roots equal or unequal

3 0
3 years ago
If cos x=8/17, and 270° &lt; x &lt; 360°<br> what is cos(2x)?
svp [43]

Answer:  \bold{-\dfrac{161}{289}}

<u>Step-by-step explanation:</u>

Given: cos x = \dfrac{8}{17}, x is in Quadrant 4

Use Pythagorean Theorem to find sin x:

8² + y² = 17²    

      y² = 17² - 8²

      y² = 289 - 64

      y² = 225

      y = 15

→    sin x = -\dfrac{15}{17}

Use the double angle formula to find cos (2x):

cos (2x) = cos^2 x - sin^2 x\\\\.\qquad=\bigg(\dfrac{8}{17}\bigg)^2-\bigg(-\dfrac{15}{17}\bigg)^2\\\\\\.\qquad=\dfrac{64}{289}-\dfrac{225}{289}\\\\\\.\qquad=-\dfrac{161}{289}

             

8 0
4 years ago
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