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elixir [45]
3 years ago
7

How does tan^-1(17/2)=83.3?

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0

Put your calculator in <em>degrees mode</em>.

1.45 is the correct number of <em>radians</em>.

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If you save $3,000 at an interest rate of
juin [17]
Amount earned in compound interest = P(1 + r)^n; where P is the principal, r is the rate and n is the number of periods.

Amount = 3,000(1 + 14%)^6 = 3,000(1 + 0.14)^6 = 3,000(1.14)^6 = $6,584.91
7 0
2 years ago
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Please answer the question in the picture below
Elanso [62]
The answer is b because there is a negative in the exponent and the number needs to be a single digit and 54 is double digit. hope this helps!
5 0
3 years ago
(the dimensions are shown in the picture)
Oksanka [162]

Answer:

Total surface area of the prism =145.32 Square centimeters

Step-by-step explanation:

The given figure is a rectangular prism with the given dimensions of :

length(L)= 10.3 cm

Width(W)=2.2 cm

Height(H)=4 cm

Total surface area of the rectangular prism is:

= 2(L*W+W*H+H*L)\\\\=2((10.3*2.2)+(2.2*4)+(4*10.3))\\\\=2(22.66+8.8+41.2)\\\\=2(72.66)\\\\=145.32cm^2\\\\

Total surface area of the prism is 145.32 Square centimeters

6 0
2 years ago
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Match each set of vertices with the type of triangle they form.
Andrew [12]

Answer:  The calculations are done below.


Step-by-step explanation:

(i) Let the vertices be A(2,0), B(3,2) and C(5,1). Then,

AB=\sqrt{(2-3)^2+(0-2)^2}=\sqrt{5},\\\\BC=\sqrt{(3-5)^2+(2-1)^2}=\sqrt{5},\\\\CA=\sqrt{(5-2)^2+(1-0)^2}=\sqrt{10}.

Since, AB = BC and AB² + BC² = CA², so triangle ABC here will be an isosceles right-angled triangle.

(ii) Let the vertices be A(4,2), B(6,2) and C(5,3.73). Then,

AB=\sqrt{(4-6)^2+(2-2)^2}=\sqrt{4}=2,\\\\BC=\sqrt{(6-5)^2+(2-3.73)^2}=\sqrt{14.3729},\\\\CA=\sqrt{(5-4)^2+(3.73-2)^2}=\sqrt{14.3729}.

Since, BC = CA, so the triangle ABC will be an isosceles triangle.

(iii) Let the vertices be A(-5,2), B(-4,4) and C(-2,2). Then,

AB=\sqrt{(-5+4)^2+(2-4)^2}=\sqrt{5},\\\\BC=\sqrt{(-4+2)^2+(4-2)^2}=\sqrt{8},\\\\CA=\sqrt{(-2+5)^2+(2-2)^2}=\sqrt{9}.

Since, AB ≠ BC ≠ CA, so this will be an acute scalene triangle, because all the angles are acute.

(iv) Let the vertices be A(-3,1), B(-3,4) and C(-1,1). Then,

AB=\sqrt{(-3+3)^2+(1-4)^2}=\sqrt{9}=3,\\\\BC=\sqrt{(-3+1)^2+(4-1)^2}=\sqrt{13},\\\\CA=\sqrt{(-1+3)^2+(1-1)^2}=\sqrt 4.

Since AB² + CA² = BC², so this will be a right angled triangle.

(v) Let the vertices be A(-4,2), B(-2,4) and C(-1,4). Then,

AB=\sqrt{(-4+2)^2+(2-4)^2}=\sqrt{8},\\\\BC=\sqrt{(-2+1)^2+(4-4)^2}=\sqrt{1}=1,\\\\CA=\sqrt{(-1+4)^2+(4-2)^2}=\sqrt{13}.

Since AB ≠ BC ≠ CA, and so this will be an obtuse scalene triangle, because one angle that is opposite to CA will be obtuse.

Thus, the match is done.

4 0
3 years ago
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Oliver drove the first 90 miles of his journey in 1.5 hours and the remaining 120 miles in 3 hours. What was the total average s
podryga [215]

90+120 miles/1.5+3 hours = 210 miles/4.5 hours = 46.67

7 0
2 years ago
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