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Lana71 [14]
3 years ago
13

There are 50 students in the fifth grade one day 20% of them were absent how many fifth graders were in class that day

Mathematics
1 answer:
cricket20 [7]3 years ago
8 0
10 students were absent that day, so 40 students were in class.
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How many times larger is 70 than 7
ozzi

the answer is 10! because 7*10= 70

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3 years ago
A family owns two businesses that made a combined profit of $$$10 million in the previous financial year, with business B making
Archy [21]

Answer:

The equation to find the profit made by business combined is x+4x = 10.

Business A made $2 million profit and Business B made $8 million profit.

Step-by-step explanation:

Given:

Profit made in previous financial year = $10 million

We need to write an equation to find the profit made by the business.

Solution:

Let the profit (in millions) made by  business A be 'x'.

Let the profit (in millions) made by  business B be 'y'.

Now given:

business B making 4 times as much profit as business A.

so we can say that;

y =4x

Now we know that;

Profit made in previous financial year is equal to sum of profit (in millions) made by  business A and profit (in millions) made by  business B.

framing in equation form we get;

x+y =10\ million

Substituting the value of y in above equation we get;

x+4x = 10

Hence The equation to find the profit made by business combined is x+4x = 10.

On Solving above equation we get;

5x =10\\\\x =\frac{10}{5} = \$2 \ million

profit (in millions) made by  business A = \$2 \ million

profit (in millions) made by  business B = 4x =4\times 2 =\$8 \ million

Hence Business A made $2 million profit and Business B made $8 million profit.

8 0
3 years ago
Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A
iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA

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3 years ago
Special right traingles (30, 60, 90<br> 45, 45, 90
igor_vitrenko [27]

Answer:

30

Step-by-step explanation:

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3 years ago
What is the Greatest Common Factor of 96x2 and 88x?
hodyreva [135]

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4 0
2 years ago
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