Answer:
The maximum amount of money the chemistry club can spend without going over their buget is $81.4 ... With a total of 6 hours their allowed to use the room for.
Step-by-step explanation:
$49 is our constant and will not change. 5.40 however will. Let's use variable h for the amount hours they can rent the room for. Now we can make an inequality;
49+ 5.40h < 86.80
5.40h < 86.80
5.4h< 37.8
h< 7
Now that we know h will have to be less than seven for the chemistry club to spend less than their buget we can find that 6 is the maxium amount of hours they can spend in the room while staying within their budget.
(This answer does not consider decimals or half hours)
Use PEMDAS
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Answer:
Step-by-step explanation:
Let the number of games is g
<u>Total cost at Mar Vista:</u>
<u>Total cost at Pinz:</u>
<u>Since same amount spent in both places, we have:</u>
- 3.5g + 2 = 3.25g + 5
- 3.5g - 3.25 = 5 - 2
- 0.25g = 3
- g = 3/0.25
- g = 12
Answer: Odds in favor = Number of successes: Number of failures
Step-by-step explanation:
Example
A jewelry box contains 5 white pearl, 2 gold rings and 6 silver rings. What are the odds of drawing a white pearl from the jewelry box?
Number of successes = 5
Number of failures = 2 + 6 = 8
Numbers of ways to draw a white pearl: number of ways to draw another jewelry.
5:8
The odds are 5:8
