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max2010maxim [7]
3 years ago
8

Please solve both questions.

Mathematics
1 answer:
Juliette [100K]3 years ago
4 0
Salad and pbj: 24 students
Turkey sandwich and school lunch: 30 students
30
-
24
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6
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What is w/5 - 5 > -8?
ki77a [65]

Answer:

w > -15

Step-by-step explanation:

(w/5-5>-8)5

w-25>-40

w>-40+25

w > -15

3 0
3 years ago
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Consider the system of equations given in slope-intercept form. y = −13x + 17, y = 5x - 23 The solution seems to be about (8, 14
bogdanovich [222]

Answer:

The exact solution for this equation would be (2.222, -11.889)

Step-by-step explanation:

Since it told us to use a graphing calculator, I went on to desmos graphing calculator, typed in the equation, then I found out where the two line intersect, and then that was the answer.

4 0
4 years ago
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Solve this equation log3X + log3(x-6) = log3 7
ExtremeBDS [4]

Hello!

log₃(x) + log₃(x - 6) = log₃(7) <=>

<=> log₃(x * (x - 6)) = log₃(7) <=>

<=> log₃(x² - 6x) = log₃(7) <=>

<=> x² - 6x = 7 <=>

<=> x² - 6x - 7 = 0 <=>

<=> x² + x - 7x - 7 = 0 <=>

<=> x * (x + 1) - 7 * (x + 1) = 0 <=>

<=> (x + 1) * (x - 7) = 0 <=>

<=> x + 1 = 0 and x - 7 = 0 <=>

<=> x = -1 and x = 7, x ∈ { 6; +∞ } <=>

<=> x = 7

Good luck! :)

3 0
3 years ago
What are unknown coefficients?
Zinaida [17]

Answer:

there is 3 solutions

Step-by-step explanation:

3 0
4 years ago
RectangleABCD has vertices at A(– 3, 1),B(– 2, – 1),C(2, 1), andD(1, 3). What is the area, in square units, of this rectangle? A
Anna [14]

Answer:

Option A. 10\ units^{2}

Step-by-step explanation:

we know that

The area of the rectangle is equal to

A=LW

where

L is the length of rectangle

W is the width of rectangle

we have

A(-3,1),B(-2,-1),C(2,1),D(1,3)

Plot the vertices

see the attached figure

L=AD=BC

W=AB=DC

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

<em>Find the distance AD</em>

A(-3,1),D(1,3)

substitute in the formula

AD=\sqrt{(3-1)^{2}+(1+3)^{2}}

AD=\sqrt{(2)^{2}+(4)^{2}}

AD=\sqrt{20}

AD=2\sqrt{5}\ units

<em>Find the distance AB</em>

A(-3,1),B(-2,-1)

substitute in the formula

AB=\sqrt{(-1-1)^{2}+(-2+3)^{2}}

AB=\sqrt{(-2)^{2}+(1)^{2}}

AB=\sqrt{5}

AB=\sqrt{5}\ units

Find the area

A=(2\sqrt{5})*(\sqrt{5})=10\ units^{2}

4 0
3 years ago
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