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mariarad [96]
3 years ago
6

you make homemade pop balm. About 11% of the lip balm is made from beeswax. You make 4 2/5 teaspoons of the lip balm. About how

many teaspoons of beeswax do you need? Round your answer to the nearest 10th.
Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
7 0
Which is 0.5 =the answer hope it helps
valina [46]3 years ago
6 0
We find how many teaspoons of beeswax we need for 4 2/5(or 22/5) teaspoons of lip balm by multiplying that by 11%. We get 2.42/5, which is ≈ 0.5 teaspoons of beeswax, to the nearest tenth.
---
Hope this helps!
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Jen borrowed 1500 from her parents for car repair. She plans to take 10% of her $450 weekly income to pay them back. At this rat
7nadin3 [17]

Answer:

10% of %450 is $45

SO 1500 divide by $45 is 33.33333

SO it will take a little over 33 weeks

Step-by-step explanation:


5 0
3 years ago
$265 worth of tickets were sold Adult tickets cost $6 Child tickets cost $2.50 • 57 tickets were sold. How many adult tickets we
BARSIC [14]

Answer:

35 adult tickets were sold

Step-by-step explanation:

If 35 adult tickets were sold, that would be $210

If 22 child tickets were sold, that would be $55

When you add them together, you get 57 tickets and $265.

(I'm sorry I don't know how to explain this but I hope it helped anyway)

5 0
2 years ago
A tennis instructor chargers $40 for each one hour lesson and $25 for each half hour lesson if the instructors I come from 35 le
kaheart [24]
X = 1 hr lessons and y = 1/2 hr lessons

x + y = 35......y = 35 - x
40x + 25y = 1115

40x + 25(35 - x) = 1115
40x + 875 - 25x = 1115
40x - 25x = 1115 - 875
15x = 240
x = 240/15
x = 16 <=== there are 16 one-hr lessons
and 19 half-hr lessons
7 0
3 years ago
Work out the formula of the nth term in the following quadratic sequence:<br> 19, 15, 9, 1...
Butoxors [25]

In a quadratic sequence we'll get a linear first difference and a constant second difference.  Let's verify that.

n          1   2   3   4

f(n)       19  15  9   1

1st diff   -4  -6  -8

2nd diff     2   2

We see that we got a constant second difference.  We could just extend that and work back up to get more values.

n          1   2   3   4       5    6      7

f(n)       19  15  9   1      -9   -21   -35

1st diff   -4  -6  -8   -10  -12   -14

2nd diff     2   2    2     2    2

That's just an aside; we're after the general formula.  We have

f(1)=19, f(2)=15, f(3)=9

In general we can assume

f(n) = an²  + bn + c

We get three equations in three unknowns,

19 = a(1²)+b(1)+c = a+b+c

15 = a(2²) + b(2) + c = 4a + 2b + c

9 = a(3²) + b(3) + c =  9a + 3b + c

That's a 3x3 linear system; it's easy to solve directly.  Subtracting pairs,

4 = -3a - b

6 = -5a - b

Subtracting those,

-2 = 2a

a = -1

b = -3a -4 = -1

c = 19-a-b = 21

Answer: f(n) = -n² - n + 21

Check:

f(1) = -1 - 1 + 21 = 19, good

f(2) = -4 - 2 + 21 = 15, good

f(3) = -9 - 3 + 21 = 9, good

f(4) = -16 - 4 + 21 = 1, good

Let's check our extended table, how about

f(7)= -49 - 7 + 21 = -35, good

6 0
3 years ago
If a graph shows the function y=3x what are the coordinates of the intercepts
vladimir2022 [97]

Answer:

graph{3x+5 [-10, 10, -5, 5]}

x

intercept:  

x

=

−

5

3

 

y

intercept:  

y

=

5

Explanation:

For a linear graph, the quickest way to sketch the function is to determine the  

x

and  

y

intercepts and draw a line between the two: this line is our graph.

Let's calculate the  

y

intercept first:

With any function,  

y

intercepts where  

x

=

0

.

Therefore, substituting  

x

=

0

into the equation, we get:

y

=

3

⋅

0

+

5

y

=

5

Therefore, the  

y

intercept cuts through the point (0,5)

Let's calculate the  

x

intercept next:

Recall that with any function:  

y

intercepts where  

x

=

0

.

The opposite is also true: with any function  

x

intercepts where  

y

=

0

.

If we substitute  

y

=

0

, we get:

0

=

3

x

+

5

Let's now rearrange and solve for  

x

to calculate the  

x

intercept.

−

5

=

3

x

 

−

5

3

=

x

Therefore, the  

x

intercept cuts through the point  

(

−

5

3

,

0

)

.

Now we have both the  

x

and  

y

intercepts, all we have to do is essentially plot both intercepts on a set of axis and draw a line between them

The graph of the function  

y

=

3

x

+

5

:

graph{3x+5 [-10, 10, -5, 5]}



3 0
3 years ago
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