We have a three unknown, 4 equation homogeneous system. These always have at least (0,0,0) as a solution. Let's write the equations, one column at a time.
1a + 0b + 0c = 0
-1a + 1b +0c = 0
0a - 1b + c = 0
0a + 0b + -1 c = 0
We could do row reduction but these are easy enough not to bother.
Equation 1 says
a = 0
Equation 4 says
c = 0
Substituting in the two remaining,
-1(0) + 1b + 0c = 0
b = 0
0(0) - 1b + 0 = 0
b = 0
The only 3-tuple satisfying the vector equation is (a,b,c)=(0,0,0)
Answer:
d. am
Step-by-step explanation:
nces am late for the movie last we night :3
Answer:
b 146
Step-by-step explanation:
2 hours = 120 minutes
120 + 26 = 146
Answer:
b
Step-by-step explanation:
because it passes the vertical line test and A does not if you look at x = 1 there are 2 points along that point (1,3) (1,-1)