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3 years ago

Two exponential functions, f and g, are shown in the figure below, where g is a transformation of f.

Mathematics

1 answer:

Vlad [161]3 years ago

3 0

Answer:

A) g(x)=f(x)-4

Step-by-step explanation:

This is a vertical shift going down. Here is an attachment of my notes on how this transforms a function:

*the note pertaining specifically to this problem starts on the line above the second hole, saying "down three"

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Simplify each equation. Tell whether the equation has one, no, or infinite solutions. 3x-7=3(x-3)+2

STatiana [176]

Answer: Infinite solutions

Step-by-step explanation: 3x -7 = 3(x-3)+2

3x + -7 = (3)(x) + (3)(-3) + 2

3x + -7 = 3x + -9 + 2

3x - 7 = (3x) + (-7)

3x -7 - 3x = 3x - 7 - 3x

-7 + 7 = -7 + 7

0 = 0

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3 years ago

The triangular numbers are defined by the recursive formula t1 = 1, tn = tn - 1 + n, where n ∈N and n > 1. What are the first

GalinKa [24]

ANSWER

C) 1, 3, 6, 10, 15, 21, 28, 36, 45

EXPLANATION

The recursive formula is,

$t_1=1,t_n=t_{n-1}+n$

when n is a natural number greater than 1.

When n=2,

$t_2=t_{2-1}+2$

$t_2=t_{1}+2 = 1 + 2 = 3$

when n=3,

$t_3=t_{2}+2 = 3 + 3= 6$

when t=4,

$t_4=t_{3}+2 = 6+ 4= 10$

When t=5,

$t_5=t_{4}+5 = 10 + 5 = 15$

when t=6,.

$t_6=t_{5}+6 = 15 + 6 = 21$

when t=7

$t_7=t_{6}+7 = 21 + 7 = 28$

When t=8,

$t_8=t_{7}+8 = 28 + 8 = 36$

When t=9,

$t_9=t_{8}+9 = 36 + 9 = 45$

Hence the first nine triangular number are

C) 1, 3, 6, 10, 15, 21, 28, 36, 45

3 0

3 years ago

A six sided number cube is rolled. What is the probability of getting three and then four, given that the first number rolled wa

LiRa [457]

Answer:

$\frac{3}{6?}$

7 0

3 years ago

What is the equation for the plane illustrated below?

TiliK225 [7]

Answer:

Hence, none of the options presented are valid. The plane is represented by $3 \cdot x + 3\cdot y + 2\cdot z = 6$ .

Step-by-step explanation:

The general equation in rectangular form for a 3-dimension plane is represented by:

$a\cdot x + b\cdot y + c\cdot z = d$

Where:

$x$ , $y$ , $z$ - Orthogonal inputs.

$a$ , $b$ , $c$ , $d$ - Plane constants.

The plane presented in the figure contains the following three points: (2, 0, 0), (0, 2, 0), (0, 0, 3)

For the determination of the resultant equation, three equations of line in three distinct planes orthogonal to each other. That is, expressions for the xy, yz and xz-planes with the resource of the general equation of the line:

xy-plane (2, 0, 0) and (0, 2, 0)

$y = m\cdot x + b$

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Where:

$m$ - Slope, dimensionless.

$x_{1}$ , $x_{2}$ - Initial and final values for the independent variable, dimensionless.

$y_{1}$ , $y_{2}$ - Initial and final values for the dependent variable, dimensionless.

$b$ - x-Intercept, dimensionless.

If $x_{1} = 2$ , $y_{1} = 0$ , $x_{2} = 0$ and $y_{2} = 2$ , then:

Slope

$m = \frac{2-0}{0-2}$

$m = -1$

x-Intercept

$b = y_{1} - m\cdot x_{1}$

$b = 0 -(-1)\cdot (2)$

$b = 2$

The equation of the line in the xy-plane is $y = -x+2$ or $x + y = 2$ , which is equivalent to $3\cdot x + 3\cdot y = 6$ .

yz-plane (0, 2, 0) and (0, 0, 3)

$z = m\cdot y + b$

$m = \frac{z_{2}-z_{1}}{y_{2}-y_{1}}$

Where:

$m$ - Slope, dimensionless.

$y_{1}$ , $y_{2}$ - Initial and final values for the independent variable, dimensionless.

$z_{1}$ , $z_{2}$ - Initial and final values for the dependent variable, dimensionless.

$b$ - y-Intercept, dimensionless.

If $y_{1} = 2$ , $z_{1} = 0$ , $y_{2} = 0$ and $z_{2} = 3$ , then:

Slope

$m = \frac{3-0}{0-2}$

$m = -\frac{3}{2}$

y-Intercept

$b = z_{1} - m\cdot y_{1}$

$b = 0 -\left(-\frac{3}{2} \right)\cdot (2)$

$b = 3$

The equation of the line in the yz-plane is $z = -\frac{3}{2}\cdot y+3$ or $3\cdot y + 2\cdot z = 6$ .

xz-plane (2, 0, 0) and (0, 0, 3)

$z = m\cdot x + b$

$m = \frac{z_{2}-z_{1}}{x_{2}-x_{1}}$

Where:

$m$ - Slope, dimensionless.

$x_{1}$ , $x_{2}$ - Initial and final values for the independent variable, dimensionless.

$z_{1}$ , $z_{2}$ - Initial and final values for the dependent variable, dimensionless.

$b$ - z-Intercept, dimensionless.

If $x_{1} = 2$ , $z_{1} = 0$ , $x_{2} = 0$ and $z_{2} = 3$ , then:

Slope

$m = \frac{3-0}{0-2}$

$m = -\frac{3}{2}$

x-Intercept

$b = z_{1} - m\cdot x_{1}$

$b = 0 -\left(-\frac{3}{2} \right)\cdot (2)$

$b = 3$

The equation of the line in the xz-plane is $z = -\frac{3}{2}\cdot x+3$ or $3\cdot x + 2\cdot z = 6$

After comparing each equation of the line to the definition of the equation of the plane, the following coefficients are obtained:

$a = 3$ , $b = 3$ , $c = 2$ , $d = 6$

Hence, none of the options presented are valid. The plane is represented by $3 \cdot x + 3\cdot y + 2\cdot z = 6$ .

8 0

3 years ago

Ronda has 34.27 in her checking account. She deposits $25.00 into her account and then writes a check for $59.99. What is Ronda'

Inga [223]

-0.72 because u can’t write a check and u don’t have the funds

4 0

3 years ago