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Marina86 [1]
3 years ago
15

In order for the data in the table to represent a linear function with a rate of change of –8, what must be the value of m? m =

2 m = 3 m = 19 m = 35
Mathematics
2 answers:
pogonyaev3 years ago
4 0
19 because it's being subtracted by 8
Morgarella [4.7K]3 years ago
4 0
19 is the answer just took the test and got it right :)
l_lxry
2 years ago
bullshit
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Plsss help no one answered the other times I put this question
svetlana [45]

Answer:

a) <em>The equation</em> (10s + 8w) <em>represents </em><em>the </em><em>calories </em><em>Bridget </em><em>ate </em><em>on </em><em>Monday </em><em>and </em><em>the </em><em>equation</em> (20s + w) <em>represents </em><em>the </em><em>calories</em><em> </em><em>she </em><em>ate</em><em> </em><em>the </em><em>next </em><em>day.</em>

<em>b)</em><em> </em><em>The </em><em>number </em><em>of </em><em>calories</em><em> </em><em>in </em><em>each </em><em>strawberry</em><em> </em><em>is </em>4 <em>and </em><em>the </em><em>number </em><em>of </em><em>calories </em><em>in </em><em>each </em><em>vanilla</em><em> </em><em>wafer</em><em> cookie</em><em> </em><em>is </em>19. The solution is s= 4 and w = 19.

Step-by-step explanation:

For part A, Bridget ate 10 strawberries and 8 vanilla wafer cookies on Monday. Since the the number of calories in a strawberry is <em>s</em> and the number of calories in a vanilla wafer cookie is <em>w </em>, the number of calories Bridget ate on Monday is <em>10s + 8w</em><em>.</em><em> </em>The next day, Bridget ate 20 strawberries and 1 vanilla wafer cookie. Hence, the number of calories Bridget ate on the next day is 20s<em> + w</em>.

For part B,

we will create two different simultaneous equations.

Equation 1: 10s + 8w = 192

Equation 2: 20s + w = 99

We need to find one of the terms first to solve the other term. For this case, I will solve for w first.

Multiply the first equation by 2.

Equation 3: 20s + 16w = 192*2 = 384.

Now, subtract equation 2 from this new equation.

Equation 4:

(20s + 16w) - (20s + w) = 384 - 99

20s + 16w - 20s - w = 285

15w = 285

This leaves only w left and we can solve w.

w = 285 / 15 = 19

Now, we can solve for s using equation 2.

20s + 19 = 99

20s = 99-19 = 80

Hence,

s = 80/20 = 4

7 0
3 years ago
"Suppose that you are a city planner who obtains a sample of 20 randomly selected members of a mid-sized town in order to determ
frosja888 [35]

Answer: 2.093

Step-by-step explanation:

As per give , we have

Sample size : n= 20

Degree of freedom : df= n-1=19

Significance level : \alpha: 1-0.95=0.05

Since , the sample size is small (n<30) so we use t-test.

For confidence interval , we find two-tailed test value.

Using students's t-critical value table,

Critical t-value : t_{\alpha/2, df}=t_{0.025,19}=2.093

Thus, the critical value for the 95% confidence interval = 2.093

4 0
3 years ago
Pam’s grandfather has a garden that measures 4 feet by 6 feet. How much will the area be increased if he doubles the length and
ExtremeBDS [4]

Answer:

The area will be increased by 72 feet.

Step-by-step explanation:

4 x 6 = 24

Now we have to double those lengths.

We know that 4 x 2 is 8 and 6 x 2 is 12.

So the new equation would be: 8 x 12 = 96

Now we take the original area and subtract it by the new area.

96 - 24 = 72

Hope this helps:)

7 0
1 year ago
You are painting the outside of a 36-foot fence that goes around a square playground. There are 4 equal sections. You have paint
kvv77 [185]
36/4 x 1/4 = 36/16 or 2 4/16 or 2 1/4
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10 points, 2 times 4 equals 10 points.


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3 years ago
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