If 6.000 ppl voted in the election how many were from 8 to 29 year old?

Mathematics

1 answer:

Burka [1]3 years ago

6 0

Answer: 600 people

Step-by-step explanation:

That is because if 6,000 people voted, and 10% were those ages, you would have to find what 10% of 6,000 was. Well, 10 has 1 zero and 6,000 has 3, so take off one zero from both number and you get 600 and 1. 600x1= 600.

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2. A lunch stand makes s.75 profit on each chef's salad and $1.20 profit on each Caesar salad. On a typical weekday, it sells be

kow [346]

Let's let

<u>x = the number of chef salads, x>=0</u>

<u>y = the number of Caesar salads, y>=0</u>

The constrains are:

40 <= x <= 60

35 <= y <= 50

x + y <= 100

The objective function here is F(x, y) = 0.75x + 1.20y

The corner points are (40, 35), (60, 35), (60, 40), (50, 50) and (40, 50).

F (40, 35) = 0.75*40 + 1.20*35 = $72

F (60, 35) = 0.70*60 + 1.20*35 = $84

F (60, 40) = 0.75*60 + 1.20*40 = $93

F (50, 50) = 0.75*50 + 1.20*50 = $97.50

F (40, 50) = 0.75*40 + 1.20*50 = $90

Thus, we conclude to maximize the profit 50 Chef and 50 Caesar salads should be prepared.

8 0

4 years ago

A rookie quarterback throws a football with an initial upward velocity component of 12.0 m>s and a horizontal velocity compon

natka813 [3]

Draw a diagram to illustrate the problem as shown below.

The ball is thrown from A, rises to a maximum height at B, and returns to the original level at C.
Given:
v = 12.0 m/s, vertical component of launch velocity
u = 20 m/s, horizontal component of launch velocity.
Note that g = 9.8 m/s², the acceleration due to gravity.
Wind resistance is ignored.

Part a.
The time, t, required to reach B from A is given by
0 = 12 - 9.8t
t = 12/9.8 = 1.2245 s

Answer: The time is 1.225 s (nearest thousandth)

Part b.
The height attained is
h = 12*1.2245 - 05*9.8*1.2245²
= 7.347 m

Answer: The height attained is 7.35 m (nearest hundredth) above A.

Part c.
When the ball returns the level of point A or C at time t,
0 = 12t - 0.5*9.8t²
t(12 - 4.9t) = 0
t = 0 (point A), or
t = 4.9/2 = 2.45 s (point C)
Notice that 2.45/2 = 1.225 s, which is equal to the time to reach B from A.

Answer:
The time taken to travel from A to C is 2.45 s.
This time is twice the time taken to travel from A to B.

Part d.
The horizontal distance traveled from A to C is
d = 20*2.45 = 49 m

Answer: 49 m

Part e.
x(t) = 20t for horizontal travel
y(t) = 12t - 4.9t² for vertical travel
vy(t) = 12 - 9.8t for vertical velocity
vx(t) = 20 for horizontal velocity.
Graphs of x-t, y-t, vx-t, vy-t are shown below.