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Diano4ka-milaya [45]
3 years ago
12

What is the relationship of the line 8x - 2y = 7 to the line 6x - 2y = -7

Mathematics
1 answer:
Alex787 [66]3 years ago
8 0

Answer:

Neither

Step-by-step explanation:

In a Standard from equation, Ax+By=C

slope=-A/B

1. -8/-2=4

  slope=4

2. -6/-2=3

  slope=3

No relationship.

slope are not the same nor reciprocal.

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Which equation below represents an equation in standard form?
Goshia [24]

Answer:

C

Step-by-step explanation:

standard form is ax + by = c, which is true for the third option.

7 0
2 years ago
two observers, Anna and Bryan. sight a kite at angles 44 degrees and 66 degrees. respictively. if anna is located 20m from the k
Arada [10]

Answer:

28.6m

Step-by-step explanation:

this question is very incomplete. it requires a number of assumptions to give an answer. the main one - where is Bryan located relative to Anna ? I assume diametrically on the opposite side of the kite. because he has the steeper angle, it is clear that he is nearer to the kite.

so, I guess, we have to add his distance to the kite to her distance to the kite to get the distance between her and him.

but he could be on any point on a circle around the kite to have the same viewing angle, and we would have no clue about where on that circle.

as the other extreme alternative, he could be on the same line to the kite as Anna. and then we would have to subtract his distance from her distance.

but again, we assume he is exactly on the other side of the kite.

anyway, each person creates a right-angled triangle with the kite:

there is the direct line of sight as the base line or Hypotenuse (c).

there is the line on the ground from the person to the point on the ground directly under the kite as one side.

there is the line representing the height of the kite above ground as the other side. we let this start at the height of the eyes of the watching person.

and we assume that both persons are of the same height (so the height of the kite relative to their eyes is the same for both).

let's start with Anna.

the side a of Anna's triangle is

a = 20m

angle between a and c = 44 degrees

we know the angle between a and b is 90 degrees.

therefore the angle between b and c = 180-90-44 = 46 degrees.

now we use the law of sines :

a/sin(bc) = b/sin(ac) = c/sin(ab)

we know sin(ab) = sin(90) = 1

20/sin(46) = b/sin(44)

b = 20×sin(44)/sin(46) = 19.31... m = height of the kite

now to Bryan.

now we know his b (height of the kite) = 19.32... m

his angle between a and c is 66 degrees.

his angle between a and b is also 90 degrees.

therefore his angle between b and c = 180-90-66 = 24 degrees.

19.31/sin(66) = a/sin(24)

a = 19.31×sin(24)/sin(66) = 8.6 m

based on our assumption that they are standing opposite from each other in relation to the kite their distance is

20 + 8.6 = 28.6m

3 0
3 years ago
It took Sergio 1.5 hours to read 3 chapters of a book. If he continues reading at a constant rate and the chapters are similar i
ryzh [129]

Answer:

9 hours

Step-by-step explanation:

1 chapter ≈ .5 hour

18 x .5 = 9

8 0
3 years ago
Which product will be positive?<br> -6 × 4<br> -6 × (-7)<br> -3 × 8<br> 6 × (-4)
masya89 [10]

Answer:

-6x(-7)( negative and negative = positive)

Step-by-step explanation:

-6x4= -24

-6x(-7) = 42

-3x8= -24

6x(-4) = -24

7 0
3 years ago
Read 2 more answers
4 Tan A/1-Tan^4=Tan2A + Sin2A​
Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
3 years ago
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