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3 years ago

An equation and the steps to solve it are shown below:

2 answers:

6 0

Step 1,
what i am thinking you're saying is 2x-1/4(12x+4)
so you would distribute the -1/4 to the 12x and the 4.
therefore making it a negative, not a positive.
so, i think step 1 is wrong.

Mariana [72]3 years ago

4 0

Answer:

step 1

Step-by-step explanation:

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Use slope-intercept form to write the equation of a line that has a slope of -3 and passes through the point (1.-5). Use the dro

Luden [163]

Answer:

m=-3

x1,y1=1,-5

we have,

y-y1=m(x-x1)

y-(-5)=-3(x-1)

y+5=-3x+3

3x+y+2=0 is the required eqn

5 0

3 years ago

Read 2 more answers

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

3 years ago

Subtract -7n +2 from 2n - 1

Irina18 [472]

2n - 1 - -7n + 2 You combine like terms with subtracting
2n - 7n = -5n
-1 - 2 = -3
So -7n + 2 - 2n - 1 = -5n - 3

4 0

3 years ago

Read 2 more answers

Can you solve this :-)? Identify the equation that means "eleven less than x is twenty-three" (A) x = 23 - 11. (B) x + 11 = 23.

mart [117]

Hey user!!

your answer is here (-:

given :- eleven less than x ( x - 11 ) = twenty three

final answer = x - 11 = 23

correct option is D. x - 11 = 23

if u need the value of x too, then Answer is :-

x - 11 = 23

x = 23 + 11

x = 34

cheers!!

3 0

3 years ago

6) Allison is opening up a jewelry business. She spent $56 on supplies. After $77 in sales to customers,

liraira [26]

Answer:

1 she spent 133

2 12 yd

3 his sister is 79 meters below him

4 the temp raised by 33 degrees

5 she has 92$ in her bank account

Step-by-step explanation:

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3 years ago