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3 years ago

9

A square tablecloth covers an area of 256 sq in it is folded in half some times until the area it covers is 8 sq in how many tim

es is it folded

1 answer:

Mazyrski [523]3 years ago

4 0

Answer:

8

Step-by-step explanation:

I solved it meantally, sorry if it’s wrong, if it is, I’ll give you the correct answers, let me know in the chat if it’s right or wrong.

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Please help me ASAP!!!

Mama L [17]

9/20

A percentage is the same as showing a number over 100 and if we multiply 20 by 5 we get 100. So if we multiply 9 by 5 we get 45, giving us 45/100 which can be shown as 45%.

As a decimal, well if we say 100% equals 1.0, then 45% equals 0.45

7 0

3 years ago

-29=5(2a-1)+2a i dont. Know how to solve

Aleksandr [31]

Answer:

a = -2 :)))))))))))))))))))))))

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3 years ago

Write a number sentence for the model. Let one white tile equal +1 and one black tile equal-1.

aalyn [17]

It's all black tiles

and black tile = -1

so
-14 - (- 6) = -8

Answer is D. last one

3 0

4 years ago

What is f(-x), if f(x)=2|x|+3x

a_sh-v [17]

F(-x) = 2/-x/ + 3(-x) = 2/x/ - 3x;

6 0

3 years ago

When 3010 adults were surveyed in a poll, 27% said that they use the Internet. Is it okay for a newspaper reporter to write th

tamaranim1 [39]

Answer:

Null hypothesis: $p=0.25$

Alternative hypothesis: $p \neq 0.25$

z=2.53

pv=0.0114

So based on the p value obtained and using the significance given $\alpha=0.05$ we have $p_v$ so we can conclude that we reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that they use the Internet differs from 0.25 or 25% .

Step-by-step explanation:

1) Data given and notation

n=3010 represent the random sample taken

X represent the people who says that said that they use the Internet.

$\hat p=\frac{X}{106}=0.27$ estimated proportion of people who says that said that they use the Internet.

$p_o=0.25$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that 50% of people who says that they would watch one of the television shows.:

Null hypothesis: $p=0.25$

Alternative hypothesis: $p \neq 0.25$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.27 -0.25}{\sqrt{\frac{0.25(1-0.25)}{3010}}}=2.53$

4) Statistical decision

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

We have the significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>2.53)=2*(0.0057)=0.0114$

So based on the p value obtained and using the significance given $\alpha=0.05$ we have $p_v$ so we can conclude that we reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that they use the Internet differs from 0.25 or 25% .

3 0

3 years ago