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jekas [21]
3 years ago
13

I WILL GIVE BRAINLIEST

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0

Answer:

least value = n-q

greatest value = q-n

closest to zero = q

Step-by-step explanation:

n-q = -2-1

=-3

q-n = 1-(-2)

= 3

q =1

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An independent-measures research study compares three treatment conditions using a sample of n = 5 in each treatment. For this s
slavikrds [6]

Answer: c. ​10

Step-by-step explanation:

Given : An independent-measures research study compares three treatment conditions using a sample of n = 5 in each treatment.

For this study, the three sample means are, M1 = 1, M2 = 2, and M3 = 3.

Grand mean = \overline{X}=\dfrac{M1+M2+M3}{3} [All sample have equal elements]

=\dfrac{1+2+3}{3}=2

For ANOVA,

SS_{between}=n\sum(M_i-\overline{X})^2 , where i= 1, 2 , 3

SS_{between}=5((1-2)^2+(2-2)^2+((3-2)^2)

SS_{between}=5((-1)^2+(0)^2+((1)^2)= 5(1+1)=10

Hence,the value would be obtained for SS_{between}=10 .

hence, the correct answer = c. ​10

8 0
3 years ago
The Value of x in the system of equation at the right is -2 what is the value of a? use elimination to help you find the value.
sammy [17]

2x-4y=-16
ax+4y=6      +
--------------------
2x+ax=-10;     for x=-2, 
2(-2)+a(-2)=-10
-2a=-10+4
a=-6/-2
a=3
7 0
3 years ago
Help
djverab [1.8K]

Answer:

x=7

Step-by-step explanation:

Find slope first

m-\frac{y2-y1}{x2-x1}

m=\frac{6-5}{7-7}

m=\frac{1}{0}\\

m is undefined- so it is a vertical line

x=7

6 0
3 years ago
Which simplifications of the powers of i are correct? There may be more than one correct answer.
fredd [130]

\bf i^2=-1\qquad\qquad i^3=-i\qquad \qquad i^4=1 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ i^{22}\implies i^{(4\cdot 5)+2}\implies i^{4\cdot 5}i^2\implies (i^4)^5 i^2\implies 1^5(-1)\implies -1~\dotfill \bigotimes \\\\\\ i^{11}\implies i^{(2\cdot 5)+1}\implies (i^2)^5 i\implies (-1)^5(i)\implies -i~\dotfill \checkmark

\bf i^{21}\implies i^{(4\cdot 5)+1}\implies (i^4)^5 i\implies 1^5(i)\implies i~\dotfill \checkmark \\\\\\ i^{12}\implies i^{3\cdot 4}\implies i^3 i^4\implies (-i)(1)\implies -i\dotfill \bigotimes \\\\\\ i^{20}\implies i^{4\cdot 5}\implies (i^4)^5\implies 1~\dotfill \checkmark \\\\\\ i^{26}\implies i^{(4\cdot 6)+2}\implies (i^4)^6 i^2\implies 1^6(-1)\implies -1\dotfill \checkmark \\\\\\ i^{27}\implies i^{(4\cdot 6)+3}\implies (i^4)^6 i^3 \implies 1^6(-i)\implies -i\dotfill \bigotimes

6 0
3 years ago
Question in picture. ty
sleet_krkn [62]

Answer:

input x = - 7

Step-by-step explanation:

A is modelled as y = 5x - 4

B is modelled as y = 3x + 8

We require output of A three times the output of B , then

5x - 4 = 3(3x + 8) ← distribute

5x - 4 = 9x + 24 ( subtract 9x from both sides )

- 4x - 4 = 24 ( add 4 to both sides )

- 4x = 28 ( divide both sides by - 4 )

x = - 7 ← input

5 0
3 years ago
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