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Ronch [10]
3 years ago
12

Pls help. I dont really understand these problems. fraction area and perimeter

Mathematics
1 answer:
yawa3891 [41]3 years ago
5 0

Answer:

Perimeter: 14 9/10 cm

Area: 11 7/10 cm^2

Step-by-step explanation:

First, you must find the perimeter of the rectangle. The definition of perimeter in terms of mathematics are: the continuous line forming the boundary of a closed geometric figure. To find the perimeter of any shape, you must add up all the sides. Thus:

2 1/4 + 2 1/4 + 5 1/5 + 5 1/5 = ?

To put it simpler -

2(2 1/4 + 5 1/5) =

4 5/10 + 10 4/10 =

14 9/10 cm

Then, you must find the area of the rectangle. The definition of the area are: the extent or measurement of a surface or piece of land. In other words, the amount of space an object takes up. You must multiply the length and width of the rectangle to find the area.

Formula of area:

A = L x W

A = 2 1/4 x 5 1/5

A = 9/4 x 26/5

A = 234/20

A= 11 7/10 cm^2

To sum it up, the perimeter of the rectangle is 14 9/10 cm and the area 11 7/10 cm^2.

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4 0
3 years ago
Suppose a large shipment of microwave ovens contained 12% defectives. If a sample of size 474 is selected, what is the probabili
melisa1 [442]

Answer:

P(\hat p>0.14)

And using the z score given by:

z = \frac{\hat p -\mu_p}{\sigma_p}

Where:

\mu_{\hat p} = 0.12

\sigma_{\hat p}= \sqrt{\frac{0.12*(1-0.12)}{474}}= 0.0149

If we find the z score for \hat p =0.14 we got:

z = \frac{0.14-0.12}{0.0149}= 1.340

So we want to find this probability:

P(z>1.340)

And using the complement rule and the normal standard distribution and excel we got:

P(Z>1.340) = 1-P(Z

Step-by-step explanation:

For this case we have the proportion of interest given p =0.12. And we have a sample size selected n = 474

The distribution of \hat p is given by:

\hat p \sim N (p , \sqrt{\frac{p(1-p)}{n}})

We want to find this probability:

P(\hat p>0.14)

And using the z score given by:

z = \frac{\hat p -\mu_p}{\sigma_p}

Where:

\mu_{\hat p} = 0.12

\sigma_{\hat p}= \sqrt{\frac{0.12*(1-0.12)}{474}}= 0.0149

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z = \frac{0.14-0.12}{0.0149}= 1.340

So we want to find this probability:

P(z>1.340)

And using the complement rule and the normal standard distribution and excel we got:

P(Z>1.340) = 1-P(Z

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