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belka [17]
3 years ago
7

Help me please !! Tell me the algebraic expression to 1 please !!!

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
5 0
You need to distribute the 4 to both the n and the positive 5 so you’re answer would be 4n + 20.
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C.

Because the marble is not replaced and that affects the next event where another marble is chosen.

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Roberto wrote the pattern shown below. What is the rule for following Roberto's pattern?
Molodets [167]

Answer:

its b because

Step-by-step explanation:

24÷12 is 2 and if u do 12 × 2 and keep going u will get the next answer

4 0
3 years ago
a class is planning a field trip to the aquarium. The cost of a ticket is $25.95. With the cost of transportation, each student
Citrus2011 [14]

Answer:

25.95 + 36

Step-by-step explanation:

You don't have any options so the answer I would say is 25.95 + 36, or the other way around.

Hope this helped :]

3 0
2 years ago
Find the distance between the point (-2, -3) and the line with the equation y=4-2/3x
otez555 [7]

Answer:

D = \frac{25\sqrt{13}}{13}

Step-by-step explanation:

Given

y = 4 - \frac{2}{3}x

(x_1,y_1) = (-2,-3)

Required

Determine the distance

y = 4 - \frac{2}{3}x

Write the above equation in standard form:

Ax + By + C = 0

So, we have:

\frac{2}{3}x+y  - 4 = 0

By comparison:

A = \frac{2}{3}  B = 1 and C = -4

The distance is calculated using:

D = \frac{|Ax_1 + By_1 + C|}{\sqrt{A^2 + B^2}}

Where:

(x_1,y_1) = (-2,-3)

A = \frac{2}{3}  B = 1 and C = -4

This gives:

D = \frac{|\frac{2}{3} * (-2) + 1 * (-3) - 4|}{\sqrt{(\frac{2}{3})^2 + 1^2}}

D = \frac{|-\frac{4}{3} -3 - 4|}{\sqrt{\frac{4}{9} + 1}}

Take LCM

D = \frac{|\frac{-4-9-12}{3}|}{\sqrt{\frac{4+9}{9}}}

D = \frac{|\frac{-25}{3}|}{\sqrt{\frac{13}{9}}}

D = |\frac{-25}{3}|/\sqrt{\frac{13}{9}}

D = \frac{25}{3}/\sqrt{\frac{13}{9}}

Split the square root

D = \frac{25}{3}/\frac{\sqrt{13}}{\sqrt{9}}

Change / to *

D = \frac{25}{3}*\frac{\sqrt{9}}{\sqrt{13}}

D = \frac{25}{3}*\frac{3}{\sqrt{13}}

D = \frac{25}{\sqrt{13}}

Rationalize

D = \frac{25}{\sqrt{13}} * \frac{\sqrt{13}}{\sqrt{13}}

D = \frac{25\sqrt{13}}{13}

Hence, the distance is:

D = \frac{25\sqrt{13}}{13}

4 0
3 years ago
Pls help ill give brainleist
Vinvika [58]
3 no. Answer is 33 in my gess
4 0
3 years ago
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