True us the answer too your question.
Answer:
7-5x
Step-by-step explanation:
Answer:
41.04 meters
Step-by-step explanation:
The questions which involve calculating the angles and the sides of a triangle either require the sine rule or the cosine rule. In this question, the two sides that are given are adjacent to each other the given angle is the included angle. The initial position is given by A. The tree is denoted as C and the fence post is denoted as B. Since the use of sine rule will complicate the question, it will be easier to solve this question using the cosine rule. Therefore, cosine rule will be used to calculate the length of BC. The cosine rule is:
BC^2 = AB^2 + AC^2 - 2*AB*AC*cos(BAC).
The question specifies that AC = 70 meters, BAC = 25°, and AB = 35 meters. Plugging in the values:
BC^2 = 35^2 + 70^2 - 2(35)(70)*cos(25°).
Simplifying gives:
BC^2 = 1684.091844.
Taking square root on the both sides gives BC = 41.04 meters (rounded to two decimal places).
Therefore, the distance between the point on the tree to the point on the fence post is 41.04 meters!!!
<h3>
Answer: 0.5</h3>
This is equivalent to the fraction 1/2
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Explanation:
The distance from A to B is 3 units. We can count out the spaces, or subtract the x coordinates of the two points and apply absolute value.
|A-B| = |-5-(-8)| = |-5+8| = |3| = 3
or
|B-A| = |-8-(-5)| = |-8+5| = |-3| = 3
We can say that segment AB is 3 units long.
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The distance from A' to B' is 1.5 units because...
|A'-B'| = |-2.5-(-4)| = |-2.5+4| = |1.5| = 1.5
or
|B'-A'| = |-4-(-2.5)| = |-4+2.5| = |-1.5| = 1.5
The absolute values ensure the distance is never negative.
We can say A'B' = 1.5
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Now divide the lengths of A'B' over AB to get the scale factor k
k = (A'B')/(AB)
k = (1.5)/(3)
k = 0.5
0.5 converts to the fraction 1/2.
The smaller rectangle A'B'C'D' has side lengths that are exactly 1/2 as long compared to the side lengths of ABCD.
Answer:
Password for the 1hdhhdhfhdhrhehjfujdjwjwjdjhf
Step-by-step explanation: