What is the lcm of 9 12 and 18

Mathematics

2 answers:

Luda [366]4 years ago

8 0

The LCM for this is 3.

Lilit [14]4 years ago

4 0

The multipliers of 9: 9,18,27,36,45,54,63

The multipliers of 12: 12, 24, 36,48,60,72,84

The multipliers of 18: 18,36,54, 72,90,108,126

Therefore, the LCM of 9,12, and 18 is 36

You might be interested in

An arithmetic sequence begins as follows: a1=13 a2=19 Which of the following gives the definition of its nth term?

Otrada [13]

Answer:

the nth term of the sequence is $a_n=6n+7$

Step-by-step explanation:

Given : An arithmetic sequence begins as follows: $a_1=13, a_2=19$

To find : Which of the following gives the definition of its nth term?

Solution :

The nth term of the A.P is $a_n=a+(n-1)d$

The first term is $a=a_1=13$

The common difference is $d=a_2-a_1$

$d=19-13=6$

Substitute in the formula,

$a_n=13+(n-1)6$

$a_n=13+6n-6$

$a_n=6n+7$

Therefore, the nth term of the sequence is $a_n=6n+7$

5 0

3 years ago

Wholesale cost of a telescope: $199.50; Markup: 50%, Discount: 30%,

kupik [55]

Answer:

$2147.85

Step-by-step explanation:

199.5*.5=99.75

199.5+99.75=299.25

299.25*.3=89.775

299.25-89.775=209.475

209.475*.04=8.279

209.475+8.379=217.854

7 0

3 years ago

Find the 59th term of the following arithmetic sequence. 15, 23, 31, 39

m_a_m_a [10]

$15~~,~~\stackrel{15+8}{23}~~,~~\stackrel{23+8}{31}~~,~~\stackrel{31+8}{39}~~,~~...~\hspace{10em}\stackrel{common~difference}{d=8} \\\\[-0.35em] ~\dotfill\\\\ n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\stackrel{\textit{term position}}{59}\\ a_1=\stackrel{\textit{first term}}{15}\\ d=\stackrel{\textit{common difference}}{8} \end{cases} \\\\\\ a_{59}=15+(59-1)8\implies a_{59}=15+472-8\implies a_{59}=479$