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3 years ago

Please help hurry!!!

Mathematics

1 answer:

pishuonlain [190]3 years ago

6 0

Answer:

h(x) = .5 (2)^x +.5

Step-by-step explanation:

The y intercept is when x = 0

Anything raised to the 0 power is 1

a h(0) = 1 +1 =2

b h(0) =.5 (1) +.5 = .5+.5 =1

c h(0) = 5(1) =5

d h(0) = 5(1) +.5 = 5.5

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Andy is one fourth as old as his grandfather who is 76 years old write an equation to determine whether Andy is 19 or 22 years o

iren [92.7K]

76÷4= ; x=19, you divide 76 by 4 because if he is 1/4 then it would be a group of one of the 4's, thus saying ehen you divide 76 by 4, it equals 19, so he is 19 years old, you could also do 19×4 and 22×4 to see which equals 76.

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3 years ago

Sarah is a computer engineer and manager and works for a software company. She receives a

daser333 [38]

Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = $a$

Given that:

$a_4=129\\a_{10}=207$

Formula for $n^{th}$ term of an Arithmetic Progression is given as:

$a_n=a+(n-1)d$

Where $d$ will represent the number of projects increased every year.

and $n$ is the year number.

$a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)$

Subtracting (2) from (1):

$78 = 6d\\\Rightarrow d =13$

By equation (1):

$129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90$

Number of projects in the first year = 90

b)

Number of projects in the twelfth year =

$a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233$

Each project pays $500

Earnings in the twelfth year = 233 $\times$ 500 = $116500

Sum of an AP is given as:

$S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938$

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 $\times$ 1938 = $969000

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3 years ago

The length of a rectangular poster is 9 more inches than two times its width. The area of the poster is 161 square inches. Solve

irinina [24]

Answer:

Width = 7 inches

Length = 23 inches

Step-by-step explanation:

Let :

length = 2x + 9
width = x

Equating to area :

(2x + 9)(x) = 161
2x² + 9x = 161
2x² + 9x - 161 = 0
2x² - 14x + 23x - 161 = 0
2x(x - 7) + 23(x - 7) = 0
x - 7 = 0
x = 7

Dimensions are :

Width = 7 inches
Length = 2(7) + 9
Length = 23 inches

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2 years ago

Read 2 more answers

What is 7/45 simplified

Akimi4 [234]

Answer:

it can not go any more

Step-by-step explanation:

7/45 is the simplified terms

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3 years ago

Is 7x-y=6 Independent

Stella [2.4K]

1. Slope = 7

2. x-intercept = 6/7 = 0.85714

3. y-intercept = 6/ - 1 = -6.00000

Rearrange:

Rearrange the equation by subtracting what is to the right if the equal sign from both sides of the equation:

7x-y- (6) = 0

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3 years ago