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Margarita [4]
3 years ago
9

The second side of a triangular deck is 4 feet longer than the shortest side. The third side that is 4 feet shorter than twice t

he length of the shortest side. If the perimeter of the desk is 48 feet, are the length of the three sides?
Mathematics
1 answer:
Svetlanka [38]3 years ago
5 0

The second side of a triangular deck is 4 feet longer than the shortest side

(s+4) = the 2nd side

and a third side that is 4 feet shorter than twice the length of the shortest side.

(2s-4) = the 3rd side

If the perimeter of the deck is 48 ​feet, what are the lengths of the three​ sides?

s + (s+4) + (2s-4) = 48

Combine like terms

s + s + 2s + 4 - 4 = 48

4s = 48

s = 48/4

s = 12 ft is the shortest side

I'll let you find the 2nd and 3rd sides, ensure they add up to 48

Hope this helps!

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\sqrt{4}=b\implies 2=b\\\\
-------------------------------\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

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