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Margarita [4]
3 years ago
9

The second side of a triangular deck is 4 feet longer than the shortest side. The third side that is 4 feet shorter than twice t

he length of the shortest side. If the perimeter of the desk is 48 feet, are the length of the three sides?
Mathematics
1 answer:
Svetlanka [38]3 years ago
5 0

The second side of a triangular deck is 4 feet longer than the shortest side

(s+4) = the 2nd side

and a third side that is 4 feet shorter than twice the length of the shortest side.

(2s-4) = the 3rd side

If the perimeter of the deck is 48 ​feet, what are the lengths of the three​ sides?

s + (s+4) + (2s-4) = 48

Combine like terms

s + s + 2s + 4 - 4 = 48

4s = 48

s = 48/4

s = 12 ft is the shortest side

I'll let you find the 2nd and 3rd sides, ensure they add up to 48

Hope this helps!

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melamori03 [73]

Answer:

4x cm.

Step-by-step explanation:

Suares have to have all 4 sides equal. The area of the rectangle (2x8) is 16.

16/4 = 4, so the square has sides of 4cm each to equal an are of 16. (4x4=16)

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3 years ago
Solve for x. Show your work with proper statements and notation.
9966 [12]

Answer:

x = 26

Step-by-step explanation:

The sum of the angles around point O = 360°, thus

x + 3x + 256 = 360 , that is

4x + 256 = 360 ( subtract 256 from both sides )

4x = 104 ( divide both sides by 4 )

x = 26

4 0
3 years ago
HURRYYYY
Radda [10]
There is no help me to do this sorry
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3 years ago
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How many ways can the letters in the word balloon be arranged? 210 1,260 2,520 5,040
Lapatulllka [165]

Answer:

The number of ways this can be done is 1,260 ways

Step-by-step explanation:

In this question, we are asked to calculate the number of ways in which the letters of the word balloon can be arranged.

To do this, we take into consideration those letters that are repeated and the number of times repeated. The letters are l and o and are repeated two times each.

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6 0
3 years ago
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

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3 years ago
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