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Charra [1.4K]
3 years ago
8

Find the value of x .

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
7 0
This is how you do it! Please message me if you still need help with anything.

guajiro [1.7K]3 years ago
3 0
Try photomath it might help
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Divide. −2 4/7 Enter your answer as a mixed number, in simplified form,
jarptica [38.1K]
I guess it's -24/7. So 24 divided by 7 is 3 remainder 3
The minus sign remains. So that will be -3 3/7
Hope I helped. Goodluck
5 0
3 years ago
Given that tan^2 theta=3/8,what is the value of sec theta?
algol [13]

Answer:

The value of SecФ is  \pm \sqrt{\frac{11}{8}} .

Step-by-step explanation:

Given as for trigonometric function :

tan²Ф = \frac{3}{8}

Or, tanФ = \sqrt{\frac{3}{8} }

∵ tanФ = \frac{Perpendicular}{Base}

So,  \frac{Perpendicular}{Base} =  \sqrt{\frac{3}{8} }

So, Hypotenuse² = perpendicular² + base²

or, Hypotenuse² = ( \sqrt{3} )² + ( \sqrt{8} )²

Or,  Hypotenuse² = 3 + 8 = 11

Or,  Hypotenuse = ( \sqrt{11} )

Now SecФ = \frac{Hypotenuse}{Base}

or, SecФ = \frac{\sqrt{11}}{\sqrt{8}} = \sqrt{\frac{11}{8} }

<u>Second Method</u>

Sec²Ф - tan²Ф = 1

Or, Sec²Ф = 1 +  tan²Ф

or, Sec²Ф = 1 +  \frac{3}{8}

Or, Sec²Ф = \frac{11}{8}

Or,  SecФ = \pm \sqrt{\frac{11}{8}}

Hence The value of SecФ is  \pm \sqrt{\frac{11}{8}} . Answer

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B

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