Find the value of x .
2 answers:
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An airplane is flying at a height of 5 kilometers above the ground. The distance along the ground from the airplane to the airport is 7 kilometers. What is the angle of depression from the airplane to the airport? (Write the answer to the nearest degree.)
✞ Step 1 ✞: Identify what is asked in the problem.
❒ The angle of depression from the airplane to the airport.
✞ Step 2 ✞: Use appropriate trigonometric ratio to solve the problem.
❒ Since the two legs of the right triangle are part of the problem, hence we use tangent ratio:
✞ Step 3 ✞: Solution and interpretation.
Hence, the angle of depression from the airplane to the airport is approximately 36°.
cost of one regular admission ticket = $ 10
cost of one senior citizen ticket = $ 5
<h3><u>Solution:</u></h3>Let "r" be the cost of one regular admission ticket
Let "s" be the cost of one senior citizen ticket
Given that,
<em><u>On day 1 you sold 30 Regular Admission tickets and 20 Senior Citizen tickets for a total of $400</u></em>
So we can frame a equation as:
30 Regular Admission tickets x cost of one regular admission ticket + 20 Senior Citizen tickets x cost of one senior citizen ticket = $ 400
30r + 20s = 400 ----- eqn 1
<em><u>Day two you sell 40 Regular Admission tickets and only 10 Senior Citizen tickets for a total of $450</u></em>
So we can frame a equation as:
40 Regular Admission tickets x cost of one regular admission ticket + 10 Senior Citizen tickets x cost of one senior citizen ticket = $ 450
40r + 10s = 450 ---- eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "r" and "s"</u></em>
Multiply eqn 2 by 2
80r + 20s = 900 --- eqn 3
Subtract eqn 1 from eqn 3
80r + 20s = 900
30r + 20s = 400
(-) ---------------------
50r = 500
<h3>r = 10</h3>Substitute r = 10 in eqn 1
30r + 20s = 400
30(10) + 20s = 400
300 + 20s = 400
20s = 100
<h3>s = 5</h3><em><u>Thus we have:</u></em>
cost of one regular admission ticket = $ 10
cost of one senior citizen ticket = $ 5