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3 years ago

4) Find the LCM of 20 and 9

Mathematics

2 answers:

allsm [11]3 years ago

8 0

180 is the least common multiple.

hodyreva [135]3 years ago

4 0

Answer:

least common multiple is 180

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I need help asap :):):):

Airida [17]

Answer:

3x5-3x2

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

For which values of k does the system of linear equations have zero, one, or an infinite number of solutions? [Note: not all thr

viktelen [127]

Answer:

The system has an infinite solution at k = 6, otherwise for any value of k, it has zero solution.

Step-by-step explanation:

Consider the system of linear equations:

$3x_{1} -x_{2}=2\;\;\;\;\;\;(1)\\ 9x_{1} -3x_{2}=k\;\;\;\;\;(2)$

The system of linear equations can have zero, one, or an infinite number of solutions:

simplify equation (1):

$x_{2}=3x_{1} -2$

substitute in equation (2), we get

$9x_{1} -3(3x_{1}-2)=k\\9x_{1} -9x_{1}+6=k\\0+6=k$

we cannot find the value of $x_{1}$ and $x_{2}$ .

so, there is no solution.

Multiply the equation (1) with 3 and put k is 6,

$3(3x_{1} -x_{2})=3\times2\\9x_{1} -3x_{2})=6$

it means both equations are overlapped. Then, the solution has infinite solutions.

Hence, the system has an infinite solutions at k is 6 otherwise for any value of k it has no solution.

4 0

3 years ago

3x-12y=216 solve for y fully reduced

Step2247 [10]

3x-12y=216

-3x. -3x

-12y=216-3x

÷-12. ÷-12

Y= -18+1/4x

I think

8 0

3 years ago

1/4x+2=-4 how do you do this step by step?

lutik1710 [3]

It’s a process of bringing one variable to the side with different forms of mathematical properties. First, subtract 2 from the left side and add it to the right side. Then divide 1/4x by 1/4 to get x alone, and divide the right side (-2) by 1/4, which will give you the answer to x. Let me know if you need help with anything else!

8 0

3 years ago

Read 2 more answers

If SAT scores are normally distributed with a mean of 1518 and a standard deviation of 325, find the probability that a randomly

aliya0001 [1]

Mean, x_bar = 1518
Standard deviation, sigma = 325
Range required: 1550 ≤ X ≤ 1575

Z = (X - x_bar)/sigma

Z1 = (1550-1518)/325 ≈ 0.1
Z2 = (1575-1518)/325 ≈ 0.18

From Z tables,
P(Z1) = 0.5398
P(Z2) = 0.5714

P(1550≤X≤1575) = P(Z2) - P(Z1) = 0.5714 - 0.5398 = 0.0316

The correct answer is C.

3 0

3 years ago

4) Find the LCM of 20 and 9​

4) Find the LCM of 20 and 9