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2 years ago

Match the descriptions of cross sections of three-dimensional figures to their corresponding shapes.

1 answer:

8 0

A slice of a right rectangular pyramid parallel to its basesince parallel to the base it should have the same figure to the base which is rectangle.
a slice of a right square pyramid perpendicular to its base but not through its top vortex. since not to the vortex, it will form a trapezoid
a slice parallel to the base of a right rectangular prism with a square basesince parallel to the base it should have the same figure to the base which is square

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PLEASE HELP! THiS IS DUE!!!!!!!! I Will MAKE BRAINlST

9966 [12]

Answer:

$\mathrm{26.\qua\:H\quad\:2 \dfrac{ 1 }{ 4 }\qua\:mi}$

$\mathrm{27.\qua\:D\quad\: 9\dfrac{ 1 }{ 8 }\qua\:lb}$

$\mathrm{28.\qua\:H\quad\:14.6}$

$\mathrm{29.\qua\:C\quad\:25\%}$

$\mathrm{30.\qua\:J\quad\:33.912\qua\ ft^{3} }$

Step-by-step explanation:

26.

$\mathrm{\dfrac{ 3 }{ 4 }\:mile\:per\:one\:hour}$

$\mathrm{To\:find\:how\:far\:Jet's\:cousin\:can\:walk\:in\:3\:hours\:,\:we\:multiply\:\dfrac{ 3 }{ 4 }\:by\:3}$

$3 \times \dfrac{ 3 }{ 4 }$

$\mathrm{Express\: 3 \times \left( \dfrac{ 3 }{ 4 } \right)\:as\:a\:singe\:fraction}$

$\dfrac{ 3 \times 3 }{ 4 }$

$\mathrm{Multiply\:3\:and\:3\:to\:get\:9}$

$\dfrac{ 9 }{ 4 }$

$\mathrm{Convert\:\dfrac{ 9 }{ 4 }\:to\:a\:mixed\:number}$

$2 \dfrac{ 1 }{ 4 }$

$\mathrm{So\:she\:can\:walk\:2 \dfrac{ 1 }{ 4 }\:miles\:in\:3\:hours}$

27.

$\mathrm{Since\:we\:want\:to\:find\:how\:many\:pounds\:both\:pumpkins\:weigh\:together,\:we\:have\:to\:add.}$

$5 \dfrac{ 3 }{ 4 } +3 \dfrac{ 3 }{ 8 }$

$\mathrm{Turn\:both\:mixed\:fractions\:into\:improper\:fractions}$

$\dfrac{ 23 }{ 4 } + \dfrac{ 27 }{ 8 }$

$\mathrm{Least\:common\:multiple\:of\:4\:and\:8\:is\:8}$

$\mathrm{Multiples\:of\:4}:\quad4,8,12,16,20$

$\mathrm{Multiples\:of\:8}:\quad8,16,24,32,40$

$\dfrac{ 23 }{ 4 } + \dfrac{ 27 }{ 8 }$

$\mathrm{Convert\: \dfrac{ 23 }{ 4 } \:and\: \dfrac{ 27 }{ 8 } \:to\:fractions\:with\:denominator\:8}$

$\dfrac{ 23 \times 2 }{ 4 \times 2 } + \dfrac{ 27 }{ 8 }$

$\mathrm{Simplify}$

$\dfrac{ 46 }{ 8 } + \dfrac{ 27 }{ 8 }$

$\mathrm{Since\: \dfrac{ 46 }{ 8 }\:and\:\dfrac{ 27 }{ 8 }\:have\:the\:same\:denominators,\:add\:them\:by\:adding\:their\:numerators}$

$\dfrac{ 46+27 }{ 8 }$

$\mathrm{Add\:46\:and\:27\:to\:get\:73}$

$\dfrac{ 73 }{ 8 }$

$\mathrm{Convert\:\dfrac{ 73 }{ 8 }\:to\:a\:mixed\:number}$

$9 \dfrac{ 1 }{ 8 }$

$\mathrm{Both\:pumpkins\:weighed\:9 \dfrac{ 1 }{ 8 }\:pounds\:all\:together}$

28.

Since the question is asking us "How many more miles did Alyce travel than Jason", we have to subtract the miles Jason traveled from the miles Alyce traveled.

$29.193-14.593$