8182 is your answer here :)
Answer:
a) ![P(X>2)= 1-P(X \leq 2) = 1-[P(X=0)+P(X=1)+P(X=2)]](https://tex.z-dn.net/?f=%20P%28X%3E2%29%3D%201-P%28X%20%5Cleq%202%29%20%3D%201-%5BP%28X%3D0%29%2BP%28X%3D1%29%2BP%28X%3D2%29%5D)
And we can find the individual probabilities like this:
![P(X=0) = \frac{e^{-0.8} 0.8^0}{0!}= 0.4493](https://tex.z-dn.net/?f=%20P%28X%3D0%29%20%3D%20%5Cfrac%7Be%5E%7B-0.8%7D%200.8%5E0%7D%7B0%21%7D%3D%200.4493)
![P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595](https://tex.z-dn.net/?f=%20P%28X%3D1%29%20%3D%20%5Cfrac%7Be%5E%7B-0.8%7D%200.8%5E1%7D%7B1%21%7D%3D%200.3595)
![P(X=2) = \frac{e^{-0.8} 0.8^2}{2!}= 0.1438](https://tex.z-dn.net/?f=%20P%28X%3D2%29%20%3D%20%5Cfrac%7Be%5E%7B-0.8%7D%200.8%5E2%7D%7B2%21%7D%3D%200.1438)
And replacing we got:
![P(X>2)= 1-P(X \leq 2) = 1-[0.4493+0.3595+0.1438]=0.0474](https://tex.z-dn.net/?f=%20P%28X%3E2%29%3D%201-P%28X%20%5Cleq%202%29%20%3D%201-%5B0.4493%2B0.3595%2B0.1438%5D%3D0.0474%20)
b) ![P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595](https://tex.z-dn.net/?f=%20P%28X%3D1%29%20%3D%20%5Cfrac%7Be%5E%7B-0.8%7D%200.8%5E1%7D%7B1%21%7D%3D%200.3595)
Step-by-step explanation:
Let X the random variable that represent the number of hurricanes hitting the coast of Florida annualle. We know that
The probability mass function for the random variable is given by:
And f(x)=0 for other case.
For this distribution the expected value is the same parameter
Part a
For this case we want this probability: ![P(X>2)](https://tex.z-dn.net/?f=%20P%28X%3E2%29)
And for this case we can use the complement rule like this:
![P(X>2)= 1-P(X \leq 2) = 1-[P(X=0)+P(X=1)+P(X=2)]](https://tex.z-dn.net/?f=%20P%28X%3E2%29%3D%201-P%28X%20%5Cleq%202%29%20%3D%201-%5BP%28X%3D0%29%2BP%28X%3D1%29%2BP%28X%3D2%29%5D)
And we can find the individual probabilities like this:
![P(X=0) = \frac{e^{-0.8} 0.8^0}{0!}= 0.4493](https://tex.z-dn.net/?f=%20P%28X%3D0%29%20%3D%20%5Cfrac%7Be%5E%7B-0.8%7D%200.8%5E0%7D%7B0%21%7D%3D%200.4493)
![P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595](https://tex.z-dn.net/?f=%20P%28X%3D1%29%20%3D%20%5Cfrac%7Be%5E%7B-0.8%7D%200.8%5E1%7D%7B1%21%7D%3D%200.3595)
![P(X=2) = \frac{e^{-0.8} 0.8^2}{2!}= 0.1438](https://tex.z-dn.net/?f=%20P%28X%3D2%29%20%3D%20%5Cfrac%7Be%5E%7B-0.8%7D%200.8%5E2%7D%7B2%21%7D%3D%200.1438)
And replacing we got:
![P(X>2)= 1-P(X \leq 2) = 1-[0.4493+0.3595+0.1438]=0.0474](https://tex.z-dn.net/?f=%20P%28X%3E2%29%3D%201-P%28X%20%5Cleq%202%29%20%3D%201-%5B0.4493%2B0.3595%2B0.1438%5D%3D0.0474%20)
Part b
Using the probability mass function we have:
![P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595](https://tex.z-dn.net/?f=%20P%28X%3D1%29%20%3D%20%5Cfrac%7Be%5E%7B-0.8%7D%200.8%5E1%7D%7B1%21%7D%3D%200.3595)
Answer:
y = 8.66
Step-by-step explanation:
tan 60° = y/5
1.7321= y/5
y = 8.66
Answer:
The ordered pairs are;
(-1,1) and (-2,3)
Step-by-step explanation:
Here, we want to select which ordered pair is not a solution to the given equation
The one that will not be a solution will be a point at which if we insert the x-value into the equation, we do not get the y-value at that point
For (3,7
2(3) + 1 = 7
For 0,1
2(0) + 1 = 1
For (-1,1)
= 2(-1) + 1 = -2 + 1 = -1
This is wrong
(-3,-5)
= 2(-3) + 1 = -6 + 1 = -5
(-2,3)
= 2(-2) + 1 = -4 + 1 = -3
This is wrong also
Answer:
Not 100 percent sure but i think the correct answer is the last one.
Step-by-step explanation:
I know that the answer is either the last one or before the last because they are dependent on each other. This is because the probability of both increases when they are added together. The more you have the more likely to get one of them. I went for the last one because i think that the value of together is greater than when they are added.
Again, not 100 percent sure, tried to give it my best shot.
Hope this helps.