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zysi [14]
3 years ago
10

I need help plzzzzzzzzzzzzzzzzzzzzz

Mathematics
1 answer:
blagie [28]3 years ago
3 0

Answer:

Step-by-step explanation:

Start box

180 = 89+42+x

180-89-42=x

49 = x

2nd box

180 = 84+58+x

180-84-58=x

38 = x

3rd box

180=74+2x

180-74=2x

106/2 = x

53 = x

4th box

180=102+2x

180-102=2x

78/2 = x

39 = x

4th box

180 = 73+81 +x

180-73-81=x

26 = x

5th box

180=2*54+x

180 - 2*54 = x

72 = x

6th box

180=62-2x

180-62=2x

118=2x

118/2=x

59 = x

7th box

180 = 2*68 + x

180-2*68=x

44 = x

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vagabundo [1.1K]

Answer:

11+2n

Step-by-step explanation:

Arithmetic sequence=a+(n-1)d

a=first number

n=nth term

d=difference

a=9

n=?

d=-2

So let's solve

9+(n-1)(-2)

9+(2n+2)

9+2n+2

Collect like terms

9+2+2n

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So the nth term is 11+2n

7 0
4 years ago
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Answer:

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B:(-4.009,1.018) And (-2,-3)

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Step-by-step explanation:

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3 years ago
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Define the function add_mn that takes two integers m, n as arguments and returns m + 10 * n. For instance, add_mn 3 5 = 3 + 10*5
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Answer:

// C++ Program to arithmetic operationf on 2 Numbers using Recursion

// Comments are used for explanatory purpose

#include <bits/stdc++.h>

using namespace std;

// add10 recursive function to perform arithmetic operations

int add10(int m, int n)

{

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return 0;

}

// Main Methods Starts here

int main()

{

int m, n; // 2 Variables m and n declared as integer

cin>>m; // accept input for m

cin>>n; // accept input for n

cout << "Result : "<<add10(m,n); // Print results which is calculated by m + 10 * n

return 0;

}

8 0
3 years ago
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