Answer:
I'm not sure if this is fully correct but I think it is.
Step-by-step explanation:
1)x^8
2)81y^2
3)16x^4
4)-125y^9
5)a^12b^4
6)x^32/256
7)54a^6
8)8x^10
9)-48y^4x^2
10)8192x^11y^6
11)512x^9y^3
12)-96x^14y^2
13)324m^4n^2+(n^2m/6)
14)8r^6s^10
15)6x^15y^21
Answer:
(b) 1
Step-by-step explanation:
To differentiate 
we will need the product rule:
.
We have 
, so the following equation is true by the transitive property:
By subtraction property we have:
Since 
, then we can divide both sides by 
:
This implies 
is constant.
So we have that 
where 
is a real number.
Since 
and 
, then by transitive property 
.
So 
.
Checking:
So the following conditions were met.
Answer:
c
Step-by-step explanation:
The zero product property states that if a⋅b=0 then either a or b equal zero. This basic property helps us solve equations like (x+2)(x-5)=0.
Answer:
A
Step-by-step explanation:
![h(t)-j(t)=t^{\frac{2}{3}}-9-[3t+5t^{\frac{2}{3}}]\\\\=t^{\frac{2}{3}}-9-3t-5t^{\frac{2}{3}}\\\\=t^{\frac{2}{3}}-5t^{\frac{2}{3}}-3t-9\\\\=[1-5]*t^{\frac{2}{3}}-3t-9\\\\=-4t^{\frac{2}{3}}-3t-9](https://tex.z-dn.net/?f=h%28t%29-j%28t%29%3Dt%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D-9-%5B3t%2B5t%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%5D%5C%5C%5C%5C%3Dt%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D-9-3t-5t%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%5C%5C%5C%5C%3Dt%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D-5t%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D-3t-9%5C%5C%5C%5C%3D%5B1-5%5D%2At%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D-3t-9%5C%5C%5C%5C%3D-4t%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D-3t-9)
Answer: 0
Step-by-step explanation:
You can solve for tangent by dividing sin by cos.
Looking at the unit circle, at 0, sin is 1 and cos is 0, so you would simply have 0/1, which equals zero.
