Answer:
a)1 cup of flour
b)67.5 minutes
Step-by-step explanation:
a) A recipe requires 3 cups of flour to make 27 dinner rolls. How much flour is needed to make 9 rolls?
From the above question, we know that:
27 dinner rolls = 3 cups of flour
9 dinner rolls = x
Cross Multiply
27 rolls × x = 9 rolls × 3 cups
x = 9 rolls × 3 cups/27 rolls
x = 1 cup of flour
Hence, 1 cup of flour is needed to make 9 dinner rolls
b) Mandy runs 4 km in 18 min. She plans to run in a 15 km race. How long will it take her to complete the race?
From the above question:
4 km = 18 minutes
15km = x
Cross Multiply
4km × x = 15km × 18 minutes
x = 15km × 18minutes/4km
x = 67.5 minutes
Hence, in a 15km race , it would take her 67.5 minutes to complete her race.
Answer:
Slope: 2
Step-by-step explanation:
Taking any two points on the slope: (0,1) & (1,3)
where (0,1) is (x1,y1) and (1,3) is (x2,y2)
Substituting into the slope formula as below:

= (3-1)/(1-0)
= 2/1
= 2
Hence, the slope is 2
<em>Hope this helps and be sure to have a wonderful time ahead at Brainly! :D</em>
Answer:
no
Step-by-step explanation:
First you divide it 200.96 by3.14 which it 64 then you find the square root of 64 which is 8 feet
Answer:
The expected number of children that can pass the fitness test in a test session is 7.5 and the standard deviation is 1.37.
Step-by-step explanation:
For each children, there are only two possible outcomes. Either they pass the health test, or they do not. Whether a child can pass the test is independent with the test result of other children. This means that we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:

The standard deviation of the binomial distribution is:

The probability for each child to pass the fitness test is 0.75
This means that 
10 independent children
This means that
Find the expectation and standard deviation of the number of children can pass the fitness test in a test session.


The expected number of children that can pass the fitness test in a test session is 7.5 and the standard deviation is 1.37.