Start with expression 
1. Separate terms - with x leave in left side, without x write in right side:
2. Divide the last expression by a (
):
Answer: this statement is true when .
A) because when they are equal it means that their y has the same value, which means their intersection point.
B) You should take all integers from (-2, 2) which are: -2, -1, 0, 1, 2 and put them one by one in the example:
x = -2
y1 = 4^-(-2) = 4^2 = 16
y2 = 2^(-(-2) + 1) = 2^(2+1) = 2^3 = 8
y1 ≠ y2 => so x=-2 isn't our answer
-------------------------------------------------------
x = -1
y1 = 4^-(-1) = 4^1 = 4
y2 = 2^(-(-1) + 1) = 2^(1+1) = 2^2 = 4
y1 = y2 => so our answer will be x = -1
-------------------------------------------------------
x = 0
y1 = 4^-(0) = 4^0 = 1
y2 = 2^(-(0) + 1) = 2^(0+1) = 2^1 = 2
y1 ≠ y2 => so x=0 isn't our answer
--------------------------------------------------------------
x = 1
y1 = 4^-(1) = 4^(-1) = 1/4
y2 = 2^(-(1) + 1) = 2^(-1+1) = 2^0 = 1
y1 ≠ y2 => so x=1 isn't our answer
--------------------------------------------------------------
x = 2
y1 = 4^-(2) = 4^(-2) = 1/16
y2 = 2^(-(2) + 1) = 2^(-2+1) = 2^(-1) = 1/2
y1 ≠ y2 => so x=2 isn't our answer
Which means that our final answer is: x=-1
C) You should draw both graphics, and their intersection point (x) will be the answer.
I hope it helped.
Answer:
The number of business students that must be randomly selected to estimate the mean monthly earnings of business students at one college is 64.
Step-by-step explanation:
The (1 - <em>α</em>) % confidence interval for population mean is:
The margin of error for this interval is:
The information provided is:
<em>σ</em> = $569
MOE = $140
Confidence level = 95%
<em>α</em> = 5%
Compute the critical value of <em>z</em> for <em>α</em> = 5% as follows:
*Use a <em>z</em>-table.
Compute the sample size required as follows:
![n=[\frac{z_{\alpha/2}\times \sigma}{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csigma%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{1.96\times 569}{140}]^{2}\\\\=63.457156\\\\\approx 64](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1.96%5Ctimes%20569%7D%7B140%7D%5D%5E%7B2%7D%5C%5C%5C%5C%3D63.457156%5C%5C%5C%5C%5Capprox%2064)
Thus, the number of business students that must be randomly selected to estimate the mean monthly earnings of business students at one college is 64.
Answer:
D)1
Step-by-step explanation:
4:7
divide the 44 and 77 into 11 and you get the simplest form which is 4:7
