Seven friends want to play a game. They must be divided into two teams with three people in each team and one leader. In how man

Question

4 years ago

14

y ways can they do it?

1 answer:

fiasKO [112] · Answer 1 · 2022-01-08T16:24:59+03:00

Answer:70

Step-by-step explanation:

Given

total of 7 friends need to be divided in two groups with 3 member each and 1 leader

leader can be chosen out of 7 person in $^7C_1$ ways

And 3 person out of remaining 6 persons in $^6C_3$ ways

thus a total of $^7C_1\times ^6C_3$ ways is possible

If order is not matter then

$\frac{140}{2}$ ways are possible