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3 years ago

What value of x is in the solution set of 8x - 6 > 12 + 2x?-1035

Mathematics

2 answers:

nika2105 [10]3 years ago

7 0

Answer:

Step-by-step explanation:

8x-6>12+2x

-2x -2x

6x-6>12

+6 +6

6x > 18

6x÷6. 18÷6

x=3

ArbitrLikvidat [17]3 years ago

4 0

Answer:

x = 5

Step-by-step explanation:

Given

8x - 6 > 12 + 2x ( subtract 2x from both sides )

6x - 6 > 12 ( add 6 to both sides )

6x > 18 ( divide both sides by 6 )

x > 3

The only value greater than 3 is x = 5 ← in the solution set

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3 0

3 years ago

What is the measure of the angle labeled (5x+42)° ?

barxatty [35]

We see two parallel lines crossed by a transversal.

The two labelled angles are alternate interior angles, hence they are equal.

The equality allows us to equate the two expressions and hence solve for x.

8x-3=5x+42

transpose terms

8x-5x=42+3

solve for x

3x=45

so x=45/3=15.

This means 5x+42=5*15+42=75+42=117 degrees.

4 0

3 years ago

Read 2 more answers

Help! How would I solve this trig identity?

NeTakaya

Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

$sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}$

Then the identity can be rewritten as:

$sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\$

Now we can multiply both sides by cos⁴(x) to get:

$\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)$