All categories

2 years ago

Help with this work pls

Mathematics

1 answer:

Travka [436]2 years ago

8 0

Answer:

(6, 2), (0, -2), (-3, -4)

Step-by-step explanation:

The intercepts are clearly (0, -2) and (3, 0). This eliminates the bottom two choices.

Both of these are listed in the upper left choice, but the third point there, (-6, -5), is not on the graph. This leaves only the upper right choice. Checking the remaining two points in that choice, (6, 2) and (-3, -4), confirms they are both on the graph.

You might be interested in

The midpoint of AB is M(7. – 7). If the coordinates of A are (8,-6), what are the

IRISSAK [1]

Answer: B = (6,-8)

Step-by-step explanation:

first the midpoint formula is $(\frac{x1+x2}{2},\frac{y1+y2}{2})$

then you take the x co-ordinate of A and substitute it into one of the x values in the first part of the formula:

$\frac{8+x}{2}=7$

then solve it like an equation:

$8+ x=14\\x=6$

then you take the y co-ordinate of A and substitute it into one of the y values in the second part of the midpoint formula:

$\frac{-6+y}{2} =-7$

then solve it like an equation:

$-6+y=-14\\y=-8$

∴ the answer is x=6, y= -8

which is expressed as a point, B(6,-8)

3 0

3 years ago

7 1/2 divided by 3 1 /8

FinnZ [79.3K]

Answer:

2.4 or 2 2/5

Step-by-step explanation:

6 0

3 years ago

What is the midpoint and distance between points P(3,5) and Q(7,5)

storchak [24]

The formula of a midpoint:

$M\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)$

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have the points P(3, 5) and Q(7, 5). Substitute:

$x=\dfrac{3+7}{2}=\dfrac{10}{2}=5\\\\y=\dfrac{5+5}{2}=\dfrac{10}{2}=5$

$d=\sqrt{(5-5)^2+(7-3)^2}=\sqrt{0^2+4^2}=\sqrt{4^2}=4$

<h3>Answer:</h3><h3>Midpoint = (5, 5)</h3><h3>Distance = 4</h3>

4 0

3 years ago

What values must x have so that log (x) is greater than 2? justify your answer

kotegsom [21]

Answer:

The value of x must be greater than 100.

Step-by-step explanation:

We need to find the value x for which the value of log(x) is greater than than 2.

$log(x)>2$

According to the property of logarithm, if a is a real number.

$log(x)=a \Rightarrow x=10^a$

Using the above property of logarithm, the given inequality can be rewritten as

$x>10^2$

$x>100$

We conclude that the value of log(x) is greater than 2 for real values of x which are greater than 100.

Therefore, the value of x must be greater than 100.

3 0

3 years ago

Quadrilateral ABCD is inscribed in this circle.

fgiga [73]

Assuming the sum of the opposite angle would be 180. We can easily calculate for x and ultimately solve for the angle of B. We do as follows

B + D = 180
3x-12 + x = 180
4x - 12 = 180
4x = 192
x = 48 degrees

Therefore angle B would have a measurement of 132 degrees. Hope this helps.

3 0

3 years ago

Read 2 more answers

Help with this work pls​

Help with this work pls