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3 years ago

If f(x)=4x+7 and g(x)=x^3, what is (g°f)(-1)

Mathematics

1 answer:

Annette [7]3 years ago

7 0

Answer:

The answer is (g°f)(-1) = 27

Step-by-step explanation:

* (g°f)(1) ⇒ means make the domain of g is the range of f

- At first find the value of f(-1)

- Take the answer and substitute it as the value of x for g

- So the range of f is the domain of g

∵ f(x) = 4x + 7

∵ The domain of f = -1 ⇒ x is the domain

∴ f(-1) = 4(-1) + 7 = -4 + 7 = 3 ⇒ f(-1) is the range

∵ g(x) = x³

∵ x = f(-1) = 3 ⇒ the domain of g

∴ g(3) = 3³ = 27 ⇒ the range of g

* (g°f)(-1) = 27

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3 years ago

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Answer:

There is one solution

Step-by-step explanation:

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3 years ago

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olga nikolaevna [1]

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3 years ago

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3 years ago

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mote1985 [20]

Answer:

$\large\boxed{f(x)=\dfrac{3}{2}x-1}$

Step-by-step explanation:

$\text{The slope-intercept formula:}\\\\y=mx+b\\\\m\ -\ slope\\b\ -\ y-intercept\\\\\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{From the table we hve two points (0, -1) and (2, 2). Substitute:}\\\\m=\dfrac{2-(-1)}{2-0}=\dfrac{3}{2}$

$\text{Therefore the equation is}\ f(x)=\dfrac{3}{2}x-1\\\\\text{Check for the point (4, 5):}\\\\f(4)=\dfrac{3}{2}(4)-1=(3)(2)-1=6-1=5\qquad\ CORRECT$

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3 years ago