Answer: There is no points
Step-by-step explanation:
<u>Answer-</u>
<em>Strip with </em><em>2.13 ft </em><em>width can be used. </em>
<u>Solution-</u>
A club swimming pool is 21 ft wide and 41 ft long.
Hence, the perimeter of the swimming pool is

The club members want a uniform width border around the pool.
They have enough material for 264 ft²
As they will cover the perimeter of the rectangular pool, so the length of the total used strip is equal to the perimeter of the swimming pool.
Let the width of the strip is x ft
So, the total area of the used strip is,

Putting the values,



Therefore, strip with 2.13 ft width can be used.
Answer:
I think it is C but I am not 100% sure
Step-by-step explanation:
.79 tons equals out to 1,580 pounds . Hope this helps :)
Answer:
The length for the first one is 97 degrees