The area of the washer will be the area of the smaller circle SUBTRACTED from the area of the larger circle.
Area of a circle = pi * r^2 where r is your radius (which is half the diameter).
Larger circle area = pi *(diameter/2) ^2.
Smaller circle area = pi * (13.2/2)^2 = pi * 6.6^2 = 136.8484....
So...the area of the washer = larger circle area - 136.4848...
Answer:
Yes
Step-by-step explanation:
Both quadrilaterals have two triangles. The triangles that coordinate with the triangles in the other quadrilateral are proven congruent by AAS and AA. That makes the quadrilaterals congruent.
Write 130 words about two plants in separate room and only talk to one will it grow faster. It wants me to describe your results and state the conclusion you can draw from these resultsWrite 130 words about two plants in separate room and only talk to one will it grow faster. It wants me to describe your results and state the conclusion you can draw from these resultsWrite 130 words about two plants in separate room and only talk to one will it grow faster. It wants me to describe your results and state the conclusion you can draw from these resultsWrite 130 words about two plants in separate room and only talk to one will it grow faster. It wants me to describe your results and state the conclusion you can draw from these resultsWrite 130 words about two plants in separate room and only talk to one will it grow faster. It wants me to describe your results and state the conclusion you can draw from these results<span>Write 130 words about two plants in separate room and only talk to one will it grow faster. It wants me to describe your results and state the conclusion you can draw from these results
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Answer:
its 48.139
Step-by-step explanation:
i also needed help , but i only saw this so i guessed the answer and it is 48.139.
<span>"Simplifying
0.2y = 0.5x + 0.1
Reorder the terms:
0.2y = 0.1 + 0.5x
Solving
0.2y = 0.1 + 0.5x
Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Divide each side by '0.2'.
y = 0.5 + 2.5x
Simplifying
y = 0.5 + 2.5x"</span>
