The slope m of a line passing through points P(a, b) and Q(c, d) is found using the formula:

.
Thus, the slope in A is

.
The slope in B is

.
Now, to compare 7/6 to 5/3, we can write the second fraction as 10/6.
So, the slope in A is larger than the slope in B.
Answer: A
Answer: x = -1
Step-by-step explanation:
Starting:
x-5(x+1)=3x+2
Simplify the left side:
-4x-5=3x+2
Move all the terms with an x to the left:
-7x-5=2
Move all the terms without an x to the right:
-7x=7
Divide both sides by -7:
x = -1
Answer:
x = 0
Step-by-step explanation:
Subtract 25x^2 from both sides
24x^2 + bx^2 - 25x^2 - 25x^2
Simplify
bx^2 - x^2 = 0
Factor bx^2 - x^2: x^2(b - 1)
bx^2 - x^2
Factor out common term x^2
= x^2 (b - 1)
x^2(b - 1) = 0
Using the Zero Factor Principle: If ab = 0 then a = 0 or b = 0
x^2 = 0
Apply rule x^n = 0 x = 0
x = 0