Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
8 1/2% of 4300 is 365.5
7 1/4% of 8200 is 594.5
9.2% of 3600 is 331.2
The picture won’t load please upload question with picture agai
Each one is just that whole number over one.
For instance for the number 7 it would be 7/1.
Hope this helps!
Answer:
9x^5−5x^2+7x−3
Step-by-step explanation:
2x5+3x3+−5x2+7x+1+7x5+−3x3+−4
(2x5+7x5)+(3x3+−3x3)+(−5x2)+(7x)+(1+−4)
9x^5+−5x^2+7x+−3
