Simplify the following expression. 2x^5+3x^3-5x^2+7x+1+7x^5-3x^3-4

Sunday elementary school is having its annual Read a thon. the third graders have read 573 books so fair. Their goal is to read

il63 [147K]

The answer would be 901 because they said what is the least number they would need to read and their goal is MORE than 900. The amount of books that they already had is useless information (Ignore). They love giving trick questions. :)

4 0

4 years ago

Someone please help me

MariettaO [177]

The diagram is a "mapping diagram" that describes a function? The function pairs numbers from the set on the left with numbers from the set on the right. "Domain" refers to the numbfers on the left, where the arrows come FROM. (Some people describe this as a mapping of x to y, with x on the left and y on the right.) The answer is B.

7 0

4 years ago

Calculate average rate of change between n=1 and n= 11

crimeas [40]

Answer:

The ordered pairs for 1 and 3 are:

(1,2) (3,8)

Now use the slope formula:

(y2-y1)/(x2-x1)

(8-2)/(3-1)= 6/2 = 3

Step-by-step explanation:

5 0

3 years ago

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Gibbs Baby Food Company wishes to compare the weight gain of infants using its brand versus its competitor’s. A sample of 40 bab

Leviafan [203]

Answer:

$z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936$

The p value can be founded with this formula:

$p_v =P(z$

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

Step-by-step explanation:

Information given

$\bar X_{1}=7.6$ represent the mean for Gibbs products

$\bar X_{2}=8.1$ represent the mean for the competitor

$\sigma_{1}=2.3$ represent the population standard deviation for Gibbs

$\sigma_{2}=2.9$ represent the sample standard deviation for the competitor

$n_{1}=40$ sample size for the group Gibbs

$n_{2}=55$ sample size for the group competitor

$\alpha=0.05$ Significance level provided

z would represent the statistic

Hypothesis to verify

We want to check if babies using the Gibbs brand gained less weight, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}< 0$

The statistic would be given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

Replacing the info given we got:

$z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936$

The p value can be founded with this formula:

$p_v =P(z$

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

5 0

3 years ago

W-9.25=5.45 Solve for w

Lunna [17]

Answer:

w=14.70

Step-by-step explanation:

4 0

3 years ago

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