I believe the answer is....
For solving for a
a-7= 3(b+2) ———> distribute 3(b+2)
a-7= 3b+6 ———-> add 7 on both sides
a-7= 3b+6
a+7= 3b +7 ———-> the 7’s cancel out so you’re left with....
a = 3b + 13 (That’s your answer)
Hope that helped :3
1) 10/6 = H/ 4 or 5/3 = H/2 or H = 10/3 = 3.3 m
<span>2) sin P = 3/5 (given) = sin (90-Q) = cos Q = 3/5</span>
You take the number of the colored pencils and divides it with the people in the class.
350/14 = 25
Let ABC be a triangle in the 3rd quadrant, right-angled at B.
So, AB-> Perpendicular BC -> Base AC -> Hypotenuse.
Given: sinθ=-3/5 cosecθ=-5/3
According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
Since sinθ=Perpendicular/Hypotenuse ,
AC=5 and AB=3
Substituting these values in equation (1)
〖BC〗^2=〖AC〗^2-〖AB〗^2
〖BC〗^2=5^2-3^2
〖BC〗^2=25-9
〖BC〗^2=16
BC=4 units
Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
So,cosθ=Base/Hypotenuse Cosθ=-4/5
secθ=Hypotnuse/Base secθ=-5/4
tanθ=Perpendicular/Base tanθ=3/4
cotθ=Base/Perpendicular cotθ=4/3
Answer:
The answer to your question is y = -2x + 11
Step-by-step explanation:
A (1, 9)
B (3, 5)
- Find the slope
m = - 2
- Find the line equation
y - y1 = m (x - x1)
y - 5 = -2(x - 3)
y - 5 = -2x + 6
y = -2x + 6 + 5
y = -2x + 11
