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3 years ago

Simplify: 12 = 3(4) + 2

Mathematics

2 answers:

myrzilka [38]3 years ago

5 0

Answer: Not possible

Step-by-step explanation: 12=12+2 this is an incorrect statement. As 14 cannot be equal to 12. 12 ~ 14

tekilochka [14]3 years ago

4 0

That would equal 12=14, which is untrue.

12=3(4)+2

12=12+2

12=14

and that's false.

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The combined weight of 2 identical dice, 5 identical balls and 4 identical marbles was 260 grams. The combined weight of one die

olya-2409 [2.1K]

Answer:

The total weight of one die, one ball, and one marble is 75 grams.

Step-by-step explanation:

Consider the provided information.

Let d represents the number of dice, b represents the number of balls and m represents the number of marbles.

So according to the question.

The combined weight of 2 identical dice, 5 identical balls and 4 identical marbles was 260 grams.

$2d+5b+4m=260$ ....(1)

The combined weight of one die and one marble was 55 grams.

$d+m=55$

$m=55-d$ ....(2)

3 balls weighed the same as two dice.

$3b=2d$

Multiply both sides by 5 and divide by 3.

$5b=\frac{10}{3}d$ .....(3)

Now put the value of equation 2 and 3 in equation 1.

$2d+\frac{10}{3}d+4(55-d)=260$

$2d+\frac{10}{3}d+220-4d=260$

$\frac{6d+10d-12d}{3}=40$

$4d=120$

$d=30$

Put d=30 in equation 2.

$m=55-30$

$m=25$

Put d=30 in equation 3.

$5b=\frac{10}{3}\times 30$

$5b=100$

$b=20$

The total weight (in grams) of one die, one ball, and one marble is:

$d+m+b=25+20+30$

$d+m+b=75$

The total weight of one die, one ball, and one marble is 75 grams.

8 0

3 years ago

A cruise ship can cover 19 nautical miles in 323 minutes. How many nautical miles will it travel in 102 miles?

kow [346]

1 mile is equal to 0.868976 nautical miles
Therefore 12 miles is equal to 10.427, rounded the answer is B.

Hope that was helpful.

4 0

3 years ago

A line contains the points (82, -96) and (87, -86)

Tasya [4]

Answer:

Step-by-step explanation:

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3 years ago

Nuclear Power Plant Some nuclear power plants utilize "natural draft" cooling towers in the shape of a hyperboloid, a solid obta

luda_lava [24]

Answer:

592.4 feet

Step-by-step explanation:

The cross section of the tower can be modeled by a hyperbola with its vertex at (x, y) = (100, 360) and its center at (0, 360). The point (x, y) = (200, 0) helps define the equation of it.

Basic form:

((x -h)/a)^2 -((y -k)/b)^2 = 1

Filling in (h, k) = (0, 360) and a=100, we can find b using the given point:

(200/100)^2 -((0-360)/b)^2 = 1

(360/b)^2 = 3 . . . . . . . . . . . . . . . rearrange, simplify

b^ = 360^2/3 = 43200

So, the equation of the hyperbola is ...

x^2/10000 - (y-360)^2/43200 = 1

Then for x = 150 (the distance from center at the top, we can find y to be ...

(150/100)^2 - (y -360)^2/43200 = 1

1.25 = (y -360)^2/43200

y = 360 +√(1.25·43200) ≈ 592.379

The height of the tower is about 592.4 feet.

4 0

4 years ago

2. Which relations are functions? Explain. For each graph, state the domain and range.

ale4655 [162]

Answer:

A. and C. neither of them have a repeating y value if you input a vertical line on the graph

7 0

3 years ago

Simplify: 12 = 3(4) + 2​

Simplify: 12 = 3(4) + 2