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Vesnalui [34]
3 years ago
11

If 2x + 5y = -5 what is x if y = -5 HELP ASAP

Mathematics
1 answer:
mash [69]3 years ago
7 0

Answer:

x=10

Step-by-step explanation:

first substitute y with the value (-5)

2x+5(-5)=-5 which is simplified to 2x+-25=-5

add 25 to -5 which gives you 2x=20

then divide 20 by 2 which makes x=10

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Factories A, B and C produce computers. Factory A produces 4 times as manycomputers as factory C, and factory B produces 7 times
Elina [12.6K]

Answer:

The  probability is   P(A') =  0.485

Step-by-step explanation:

Let assume that the number of computer produced by factory C is  k = 1  

 So  From the  question we are told that

       The number produced by  factory A is  4k =  4

        The  number produced by factory B is  7k  = 7

        The  probability of defective computers from A is  P(A) =  0.04

        The  probability of defective computers from B is  P(B)  =  0.02

        The  probability of defective computers from C is P(C) =  0.03

Now the probability of factory A producing a defective computer out of the 4 computers produced is  

       P(a) =  4 *  P(A)

substituting values

        P(a) =  4 * 0.04

        P(a) = 0.16

The probability of factory B producing a defective computer out of the 7 computers produced is  

       P(b) = 7  *  P(B)

substituting values

        P(b) =  7 * 0.02

        P(b) = 0.14

The probability of factory C producing a defective computer out of the 1 computer produced is  

       P(c) = 1  *  P(C)

substituting values

        P(c) =  1 * 0.03

        P(b) = 0.03

So the probability that the a computer produced from the three factory will be defective is  

     P(t) =  P(a) +  P(b) +  P(c)

substituting values

     P(t) =   0.16  + 0.14 +  0.03

     P(t) =   0.33

Now the probability that the defective computer is produced from factory A is

      P(A') =  \frac{P(a)}{P(t)}

       P(A') =  \frac{ 0.16}{0.33}

        P(A') =  0.485

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