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Yanka [14]
3 years ago
10

3x+4[2x-3(x+1)-20x]=25x+100

Mathematics
1 answer:
sashaice [31]3 years ago
6 0
Simplify:
3x + 4[2x -3x -3 -20x] = 25x +100
3x + 4(-21x -3) = 25x + 100
3x - 84x -12 = 25x + 100
-81x -12 = 25x + 100
Add 12 and Subtract 25x from each side
-106x = 112
X = -112/106
X = -56/53
^^^^^^^^^^
Final Answer^^
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What will it cost to tile a rectangular floor measuring 280 feet by 27 feet if the tile costs $11 per square foot. Round to the
lawyer [7]

Answer:

687

Step-by-step explanation:

First, we want to find the area of the rectangle.

The formula is length times width, so it is 27*280, which equals 7560. We divide this by 11 to get 687.27272727.....(repeating)

The answer is 687.

7 0
3 years ago
A = 4 units B= 3 units C= 3.5. D= 5 units
aliya0001 [1]

D would be the correct answer.

Explanation

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4 0
3 years ago
Find the value of x. Leave your answer in simplest radical form.
FrozenT [24]

Answer:

x=10.82

Step-by-step explanation:

6^2+9^2=c^2

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5 0
3 years ago
What r the answers to these questions(picture above)?PLEASE HELP
kirill [66]

Problem 3

The constant term is 290. This is the term that stays the same no matter what the value of 'a' happens to be. Contrast this with the variable term 2.50a which changes if 'a' changes (hence the name "variable" for "vary" or "change")

If Mike sold 0 accessories, then a = 0 and the expression would be

2.50*a + 290 = 2.50*0 + 290 = 290

Selling 0 accessories leads to $290. This is the amount he is guaranteed with the 2.50a portion being additional money to motivate him to sell more.

------------

Answer: Choice (3) 290, amount he is guaranteed

======================================

Problem 4

Plug y = 0 into the equation. Solve for x

9x - 14y = -3

9x - 14*0 = -3 .... replace y with 0

9x - 0 = -3

9x = -3

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x = -3/9

x = -1/3

------------

Answer: Choice (3) which is -1/3

6 0
3 years ago
(5x^3-8x^2+9x+12)/(x-3)<br><br> please answer with sentences on how to do it step by step. thanks!
Anastaziya [24]

Answer:

5x^2+7x+30+\frac{102}{x-3}

Step-by-step explanation:

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}5x^3-8x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{5x^3}{x}=5x^2\\\mathrm{Quotient}=5x^2\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}5x^2:\:5x^3-15x^2\\\mathrm{Subtract\:}5x^3-15x^2\mathrm{\:from\:}5x^3-8x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=7x^2+9x+12\\\mathrm{Therefore}\\=5x^2+\frac{7x^2+9x+12}{x-3}

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}7x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{7x^2}{x}=7x\\\mathrm{Quotient}=7x\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}7x:\:7x^2-21x\\\mathrm{Subtract\:}7x^2-21x\mathrm{\:from\:}7x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=30x+12\\\mathrm{Therefore}\\=5x^2+7x+\frac{30x+12}{x-3}\\

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}30x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{30x}{x}=30\\\mathrm{Quotient}=30\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}30:\:30x-90\\\mathrm{Subtract\:}30x-90\mathrm{\:from\:}30x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=102\\\mathrm{Therefore}\\=5x^2+7x+30+\frac{102}{x-3}

6 0
2 years ago
Read 2 more answers
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