Question

Solve using quadratic formula 5x^2-4x+3=0

Answer 1

Answer:

Impossible

Step-by-step explanation:

In 5x^2-4x+3=0, standard form, substitute these values in the quadratic formula:

a = 5; b = -4; c = 3

The quadratic formula is $x = \frac{ -b ± \sqrt{b^{2} - 4ac}}{2a}$

(ignore the weird capital A)

Substitute a b and c:

$x = \frac{-(-4) ± \sqrt{(-4)^{2} - 4(5)(3)}}{2(5)}$

Simplify:

$x = \frac{4) ± \sqrt{16 - 60}}{10}$

Because $\sqrt{16-60}$ is the square root of a negative number, the answer would be imaginary.

Therefore, there are not solutions to this equation.

A solution is the same as the roots or zeroes, where the graph would cross the x-axis when graphed.

The graph never meets the x-axis. It looks like this: