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umka2103 [35]
3 years ago
15

Please help me now please

Mathematics
1 answer:
nadezda [96]3 years ago
7 0
A2+B2=C2

12(2)+B(2)=27.1(2)

24+B=54.2
-24 -24
——————
B=30.2

Answer is 30.2
I hope this helps
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What is the LCD of 1/4a and 5/6a
inessss [21]
1/(4a) & 5/(6a)
(3)(1/4a)=3/12a
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What are the coordinates of the midpoint for segment AB if A is (14 , -2) and B is (7 , -8)
Alenkasestr [34]

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Step-by-step explanation:

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4 0
3 years ago
(-2,3)(0,8) what is en equation for these points
jenyasd209 [6]

Answer:

The line equation that passes through the given points is          5x – 2y + 16 = 0

Explanation:

Given:

Two points are A(-2, 3) and B(0, 8).

To find:

The line equation that passes through the given two points.

Solution:

We know that, general equation of a line passing through two points (x1, y1), (x2, y2) is given by

\frac{(y- y1)}{(x-x_1)}= \frac{((y_2- y_1)}{(x_2- x_1 )}

{(y- y1)= \frac{((y_2- y_1)}{(x_2- x_1 )}\times(x-x_1).............(1)

here, in our problem x1 = 0, y1 = 8, x2 = -2 and y2 = 3.

Now substitute the values in (1)

y-8 = \frac{(3-8)}{(- 2 - 0)}\times(x- 0)

y-8 = \frac{(- 5)}{(-2)}\times(x)

y-8 =\frac{5}{2}x

2y – 16 = 5x

5x – 2y + 16 = 0

Hence, the line equation that passes through the given points is 5x – 2y + 16 = 0.

4 0
3 years ago
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