What is true regarding rem sleep in infants?

1 answer:

Nutka1998 [239]3 years ago

4 0

The information is not available regrading the question and its option. The answer will consider the general points regarding the REM sleep in infants.

Answer:

Rapid eye movement (REM) sleep is the sleep that involves the rapid and random movement of the eyes. The muscle tone gets low during the REM sleep. This sleep is present in both infants and adults.

The baby start shows his legs and hands during the REM sleep. Most of the infants experience the REM sleep. The sleep become less active and the individual is more conscious during the REM sleep. The breathing of the infant is quite irregular in REM sleep.

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A man who is heterozygous for tongue rolling and has a normal vision and a woman who cannot roll her tongue and is heterozygous

Montano1993 [528]

The answer is 3/8

Let T be a dominant allele for tongue rolling and let t be a recessive allele.
Tongue-rolling is a dominant trait. That means that an individual with at least one dominant allele will have the trait:
TT - dominant homozygous individuals able to roll tongue
Tt - heterozygous individuals able to roll tongue
tt - recessive homozygous individuals able to roll tongue
A heterozygous man (Tt) and recessive homozygous female (tt) will have 2 of 4 children that are able to roll tongue (Tt). Take a look at the attached image: 2 of 4 children (marked yellow on the image) are able to roll tongue (Tt) and 2 of for children are not (tt).
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Now, let's see what happens with color blindness as an X-linked recessive trait. Let $X_V$ be a dominant allele and $X_v$ be a recessive allele. The genotypes will be as following:
$X_VX_V$ - a female with normal vision
$X_VX_v$ - a heterozygous female with normal vision
$X_vX_v$ - a female with colorblindness
$X_VY$ - a male with normal vision
$X_vY$ - a male with colorblindness
Take look at the attached image. A man with normal vision ( $X_VY$ ) and a woman heterozygous for colorblindness ( $X_VX_v$ ) will have 3 of 4 children that have normal vision (marked yellow on the image) and 1 of 4 children with color blindness.
The probability that the child has normal vision is 3/4.

Now, we have two probabilities:
The probability that a child will be able to roll his/her tongue is 1/2.
The probability that the child has normal vision is 3/4.
Since we want both of these traits to occur together, we will just multiply their possibilities:
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Explanation:

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