2 years ago

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Biology

2 answers:

goldfiish [28.3K]2 years ago

7 0

Answer:

DUH!!! Is that a question

Explanation:

lilavasa [31]2 years ago

3 0

A, B, AB would be the blood types of the offspring. A has a chance of 25% or 1/4, B has a chance of 25% or 1/4 and AB would have 2/4 or 50%.

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In the absence of recombination, how many genetically different types of gamete can an organism with six homologous chromosome p

Black_prince [1.1K]

Answer:

(D) 64

Explanation:

We have given number of chromosome pair that is haploid number = 6

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The number of garnets is given by $2^n$ where n is haploid number

In question we have given haploid number, that is n=6

So the number of gametes without recombination $=2^6=64$

So option (d) is the correct answer

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