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3 years ago

Which of these equations have no solution? Check all that apply.

Mathematics

1 answer:

Murljashka [212]3 years ago

3 0

Answer:

B and E

Step-by-step explanation:

(26x+2)+2=2(x+3)+1 - solution = 1/8

2x+3(x+5)=5(x-3) - NO SOLUTION

4x+3=x+12 - solution = 3

4 - (2x + 5) = {(-4x - 2) - solution = -1/2

5(x + 4) - X= 4(x + 5) - 1 - NO SOLUTION

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mzndndmdkdjedndidnrjen in ndir

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3 years ago

Which equation has the solutions

MatroZZZ [7]

A. .................

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4 years ago

In the midpoint rule for triple integrals we use a triple riemann sum to approximate a triple integral over a box b, where f(x,

Lana71 [14]

The sub-boxes will have dimensions $\frac{2-0}{2} \times \frac{2-0}{2} \times \frac{2-0}{2} =1\times1\times1=1 \ cubic \ units$

x sub-intervals are 0 to 1 and 1 to 2. Midpoints are at $x= \frac{1}{2}$ and $x= \frac{3}{4}$
y sub-intervals are 0 to 1 and 1 to 2. Midpoints are at $y= \frac{1}{2}$ and $y= \frac{3}{4}$
z sub-intervals are 0 to 1 and 1 to 2. Midpoints are at $z= \frac{1}{2}$ and $z= \frac{3}{4}$ 

Let $f(x,y,z)=\cos{(xyz)}$

$\int\limits \int\limits \int\limits {f(x,y,z)} \, dV \approx f\left( \frac{1}{2} , \frac{1}{2} , \frac{1}{2} \right)+f\left( \frac{1}{2} , \frac{1}{2} , \frac{3}{4} \right)+f\left( \frac{1}{2} , \frac{3}{4} , \frac{1}{2} \right)+f\left( \frac{1}{2} , \frac{3}{4} , \frac{3}{4} \right)$
$+f\left( \frac{3}{4} , \frac{1}{2} , \frac{1}{2} \right)+f\left( \frac{3}{4} , \frac{1}{2} , \frac{3}{4} \right)+f\left( \frac{3}{4} , \frac{3}{4} , \frac{1}{2} \right)+f\left( \frac{3}{4} , \frac{3}{4} , \frac{3}{4} \right) \\ \\ \approx\cos{ \frac{1}{8} }+\cos{ \frac{3}{16} }+\cos{ \frac{3}{16} }+\cos{ \frac{9}{32} }+\cos{ \frac{3}{16} }+\cos{ \frac{9}{32} }+\cos{ \frac{9}{32} }+\cos{ \frac{27}{64} } \\ \\ \approx0.9922+0.9825+0.9825+0.9607+0.9825+0.9607+0.9607 \\ +0.9123 \\ \\ \approx\bold{7.734}$

5 0

3 years ago

You have two coupons for a store. Coupon 1 is for $10 dollars off. Coupon 2 is for 15% off. Coupon 2 is for 15% off. You can onl

patriot [66]

Answer:

Purchases greater than 66.67 dollars should use coupon 2, while purchases between 20 dollars and 66.67 should use coupon 1.

Step-by-step explanation:

Coupon 1 must be used as long as those 10 dollars represent more money than 15% of coupon 2.

For example, if the purchase is the minimum of $ 20, 10 dollars represents half of the purchase, therefore in this case it is better to use coupon 1.

In this case, coupon 2 would only be a discount of 3 dollars (20 * 0.15).

So when from what value would it be better to use coupon 2, it would have to be calculated when it is worth more than 10 dollars.

10 = x * 0.15

x = 10 / 0.15

x = 66.67

That is to say that from the purchases greater than 66.67 dollars, coupon 2 would have a discount equivalent to 10 dollars or more.

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3 years ago

MARKING BRAINLIEST find a nice three terms of the geometric sequence: -3,6,-12,24

Alex787 [66]

Answer:

2nd one -48, 96,-192

Step-by-step explanation:

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3 years ago